4.905t^2 + 2.93t - 10 = 0
I have to solve for t.
How do I solve this equation step by step?
Thanks.
Have you ever heard of the quadratic formula? It's the easiest solution here.
In the quadratic formula, for any quadratic equation in the for ax^2+bx+c=0
x=(-b�}�ã(b^2-4ac))/2a
In this case:
4.905=a
2.93=b
-10=c
Think you can solve it from here? The rest is some simple arithmetic (maybe use a calculator, it could be a little easier). Hope this helped. Peace.
I could've solve it if it didn't have decimal. I'd be appreciate if you could solve it form me. Thanks
To solve the equation 4.905t^2 + 2.93t - 10 = 0, you can use the quadratic formula or factorization method. Here, I will explain the steps for using the quadratic formula:
Step 1: Identify the coefficients of the equation.
In this case, the coefficients are:
a = 4.905
b = 2.93
c = -10
Step 2: Write down the quadratic formula.
The quadratic formula is:
t = (-b ± √(b^2 - 4ac)) / (2a)
Step 3: Substitute the coefficients into the quadratic formula.
Substituting the coefficients from the equation we got earlier, we have:
t = (-2.93 ± √((2.93)^2 - 4 * 4.905 * -10)) / (2 * 4.905)
Step 4: Simplify the equation.
Now, we solve the equation:
t = (-2.93 ± √((2.93)^2 + 196.2)) / 9.81
Step 5: Evaluate the solutions.
Using a calculator, we can calculate the two possible values for t:
t ≈ -2.189
t ≈ 1.227
So, the equation 4.905t^2 + 2.93t - 10 = 0 has two solutions: t ≈ -2.189 and t ≈ 1.227.