A bag contains 3 red chips, 2 blue chips, and 1 white chip. If 2 chips are chosen from the bag (without replaceent), determine the probability that they are of different colors.
ways to get two different colors
rb
rw
bw
br
wr
wb
add the probability of each of these.
I will do the first two:
Pr(rb)=3/6*2/5
Pr(rw)=3/6*1/5
ok but how do i find the final probability?
i see how i can get the probability of a certain combination, but i don't understand how i can find that end probability.
never mind i got it
thank you so much bobpursley!
A bag contains 4 purple, 3 blue and 2 red cubes. Select 3 cubes and stack on table next to the bag. What is probability of the cubes being red, purple then blue
To determine the probability that two chips chosen from the bag are of different colors, we need to calculate the number of favorable outcomes and the total number of possible outcomes.
First, let's find the total number of possible outcomes. When two chips are chosen without replacement, there are a total of 6 chips in the bag, so there are 6 options for the first pick. After the first chip is chosen, there are 5 options left for the second pick. Therefore, the total number of possible outcomes is 6 * 5 = 30.
Next, let's calculate the number of favorable outcomes, which means choosing two chips of different colors. There are 3 red chips, so for the first pick, there are 3 options. Then there are 2 blue chips, so for the second pick, there are 2 options. Since we are choosing chips of different colors, for each pick, the number of options decreases. Therefore, the number of favorable outcomes is 3 * 2 = 6.
Finally, we can calculate the probability by dividing the number of favorable outcomes by the number of total outcomes:
Probability = Number of favorable outcomes / Number of total outcomes
Probability = 6 / 30
Probability = 1 / 5
Probability = 0.2 or 20%
So, the probability that two chips chosen from the bag are of different colors is 0.2 or 20%.