1)The difference of potential between terminals of a battery is 6V. How much work is done when a series of negative charges totaling 0.5 C are moved from one terminal to another?
2) Two parallel metal plates have opposite charges and a difference of potential of 1000V between them. a) How mcuh work in eV (electrovolts) is done in moving an electron from the negatively charged plate to the positively charged plate? b) What is this work in joules?
Please explain. Thanks :)
1) Energy = Q * (delta V)
2) Use same formula, with charge Q = e
1) To calculate the work done when moving a series of charges in an electric field, we can use the equation W = qΔV, where W is the work done, q is the charge, and ΔV is the potential difference.
Given:
Charge (q) = 0.5 C
Potential difference (ΔV) = 6V
Substituting the values into the equation, we get:
W = 0.5 C * 6 V
W = 3 Joules
Therefore, the work done when moving a series of negative charges totaling 0.5 C from one terminal to another in a battery with a potential difference of 6V is 3 Joules.
2) a) To calculate the work done in moving an electron between two charged plates, we can use the equation W = qΔV, where W is the work done, q is the charge, and ΔV is the potential difference.
Given:
Charge (q) = charge of an electron = 1.6 x 10^-19 C (Coulombs)
Potential difference (ΔV) = 1000V
Substituting the values into the equation, we get:
W = (1.6 x 10^-19 C) * (1000 V)
W = 1.6 x 10^-16 Joules
Therefore, the work done in moving an electron from the negatively charged plate to the positively charged plate is 1.6 x 10^-16 Joules.
b) To convert the work from electrovolts (eV) to joules (J), we need to use the conversion factor 1eV = 1.6 x 10^-19 J.
Given:
Work (in eV) = 1.6 x 10^-16 eV
To convert it to Joules, we can use the conversion factor:
W (in J) = Work (in eV) * 1.6 x 10^-19 J
W (in J) = (1.6 x 10^-16 eV) * (1.6 x 10^-19 J)
W (in J) = 2.56 x 10^-35 J
Therefore, the work done in moving an electron from the negatively charged plate to the positively charged plate is approximately 2.56 x 10^-35 Joules.
1) To find the work done when moving a series of negative charges from one terminal to another, we can use the formula:
work (W) = charge (Q) × potential difference (V)
In this case, the charge (Q) is given as 0.5 C, and the potential difference (V) is given as 6V.
So, the work done can be calculated as:
W = 0.5 C × 6V
W = 3 J
Therefore, the work done when moving the negative charges is 3 Joules.
2) a) To find the work done in moving an electron from the negatively charged plate to the positively charged plate, we need to consider the charge of the electron and the potential difference between the plates.
The charge of an electron is considered -1.6 × 10^(-19) Coulombs. The potential difference between the plates is given as 1000V.
So, the work done can be calculated as:
W = electron charge (Q) × potential difference (V)
W = (-1.6 × 10^(-19) C) × (1000V)
W = -1.6 × 10^(-16) C V
1 eV (electron volt) is defined as the work done by moving an electron through a potential difference of 1V. Therefore, the work done in this case is -1.6 × 10^(-16) eV.
b) To convert the work from eV to joules, we need to use the conversion factor: 1 eV = 1.6 × 10^(-19) J.
So, we can calculate the work in joules as:
W (J) = W (eV) × (1.6 × 10^(-19) J / 1 eV)
W (J) = (-1.6 × 10^(-16) eV) × (1.6 × 10^(-19) J / 1 eV)
W (J) = -2.56 × 10^(-35) J
Therefore, the work done in moving an electron from the negatively charged plate to the positively charged plate is approximately -2.56 × 10^(-35) Joules.