How would you set these to y=?
Thank you for your help.
x=2-2y
3x=-6-2y
3x=3+4y
1) add 2y to each side, subtract x from each side, then divide both sides by 2
How would you set these to y=?
Thank you for your help.
x=2-2y
3x=-6-2y
3x=3+4y
Are these correct:
3x=-6-2y; y=3/2x-3
3x=3+4y; 4y =-3x +3
I really need help. Thank You
To solve each equation for y, you need to isolate y on one side of the equation. Here's how you can do it for each equation:
1. x = 2 - 2y
Start by subtracting 2 from both sides to get rid of the constant term on the right side:
x - 2 = -2y
Then, divide both sides by -2 to isolate y:
(x - 2) / -2 = y
Finally, simplify the right side:
y = (2 - x) / 2
2. 3x = -6 - 2y
Start by adding 6 to both sides to eliminate the constant term on the right side:
3x + 6 = -2y
Then, divide both sides by -2 to isolate y:
(3x + 6) / -2 = y
Finally, simplify the right side:
y = -(3x + 6) / 2
3. 3x = 3 + 4y
Start by subtracting 3 from both sides to get rid of the constant term on the right side:
3x - 3 = 4y
Then, divide both sides by 4 to isolate y:
(3x - 3) / 4 = y
Finally, simplify the right side:
y = (3x - 3) / 4
So, the equations can be rewritten as:
1. y = (2 - x) / 2
2. y = -(3x + 6) / 2
3. y = (3x - 3) / 4
Remember, it's important to practice and apply the concepts of isolating variables to solve equations effectively.