I am having to find the value of y for the given values of x. I understand how to find the value of x, but I am unsure how to put it in the form of ordered pairs:
This is not the actual problem on my assignment:
y=7^x, for x=2
y=7^2
y=7*7
y=49
I am lost as to how I put it in ordered pairs: Would it be (2,49)?
I am not looking for the answer, just some guidance! Thanks!
I am also unclean if the exponent is negative, such as -2, does the ordered pair go in as (-2, 1/2)?
if x = -2 for y = 7^x
then
y = 7^(-2) = 1/7^2 = 1/49
ordered pair: (-2,1/49)
this is using the rule,
a^(-n) = 1/a^n
thanks!
To put the value of y in the form of ordered pairs, you need to express it as (x, y), where x represents the given value for x, and y represents the corresponding value of y that you calculated.
In your example, you calculated that y is equal to 49 when x is equal to 2. Therefore, you can express it as (2, 49) - where 2 is the x-coordinate and 49 is the y-coordinate.
In general, to find the ordered pair, you would substitute the given value of x into the equation and calculate the value of y. Then, you express it as (x, y), where x represents the given value and y represents the calculated value.