The density of gasoline is 730 kg/m^3 at 0'C. One gallon of gasoline occupies .0038 m^3. Gasoline's volume expansion coefficient is .00096'C ^-1.

How many kilograms of gasoline are obtained when 9 gallons of gasoline are bought @ 0'C rather than 18"c (temp. at the filling station)?

answer in kg???

Repeat post; already answered.

To find the mass of gasoline obtained when 9 gallons are bought at 0°C compared to 18°C, we need to take into account the change in temperature and the expansion of gasoline.

First, let's calculate the volume of 9 gallons of gasoline at 0°C. We know that one gallon of gasoline occupies 0.0038 m^3. So, 9 gallons of gasoline would occupy:
9 * 0.0038 = 0.0342 m^3.

Now, let's consider the volume expansion of gasoline. The volume expansion coefficient of gasoline is given as 0.00096°C^-1. Since we are comparing 0°C to 18°C, the temperature change is 18°C - 0°C = 18°C.

To calculate the expansion in volume, we multiply the initial volume by the temperature change and the volume expansion coefficient:
Expansion in volume = (0.0342 m^3) * (18°C) * (0.00096°C^-1).

Next, we need to calculate the final volume of gasoline at 18°C. The final volume is the sum of the initial volume and the expansion in volume:
Initial volume (at 18°C) = 0.0342 m^3 + (Expansion in volume).

Finally, to find the mass of gasoline obtained, we use the density of gasoline at 0°C, which is given as 730 kg/m^3. The mass is the product of the density and the final volume:
Mass = (Initial volume at 18°C) * (density at 0°C) = (Initial volume at 18°C) * 730 kg/m^3.

By plugging in the values we've calculated, we can find the answer in kg.