You kick a soccer ball, compressing it suddenly to 2/3 of its original volume. In the process, you do 410 J of work on the air (assumed to be an ideal gas) inside the ball.
(a) What is the change in internal energy of the air inside the ball due to being com-pressed?
(b) Does the temperature of the air inside the ball rise or fall due to being compressed? Explain.
i don't have answer, pls help me...
Q=0
delta U= -W
delta U= 410j
but since it is compression
delta U= -410j
Temp should rise since the pressure of the system increased
12
To determine the change in internal energy of the air inside the ball due to compression, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat transfer to or from the system minus the work done by the system. In this case, there is no heat transfer involved, so the change in internal energy is solely due to the work done.
(a) The work done on the air inside the ball is given as 410 J. Since the work done by a gas is equal to the negative of the work done on it, the change in internal energy is also -410 J. Therefore, the change in internal energy of the air inside the ball due to being compressed is -410 J.
(b) When a gas is compressed, its temperature generally increases. This is because compression leads to an increase in the average kinetic energy of the gas molecules, which corresponds to an increase in temperature. In this case, since the work done on the air is positive (work done on the gas), the temperature of the air inside the ball will rise due to being compressed.
To summarize:
(a) The change in internal energy of the air inside the ball due to being compressed is -410 J.
(b) The temperature of the air inside the ball will rise due to being compressed.