If you are given only the time and Molarity for example

Time Molarity
30s 0.678M
60s 0.762 M
70s 0.00987 M

How would you find the constant rate? given only Molarity and time

To find the constant rate given the molarity and time, you need to calculate the change in molarity over the change in time. Here's how you can do that:

1. Identify the initial molarity (M1) and the final molarity (M2).

2. Calculate the change in molarity (∆M) by subtracting the initial molarity from the final molarity (∆M = M2 - M1).

3. Identify the initial time (t1) and the final time (t2).

4. Calculate the change in time (∆t) by subtracting the initial time from the final time (∆t = t2 - t1).

5. Finally, calculate the constant rate (r) by dividing the change in molarity by the change in time (r = ∆M/∆t).

Note: Make sure the time units are consistent (e.g., seconds, minutes, hours) throughout the calculations.

Let's apply these steps to your example:

M1 = 0.678 M
M2 = 0.00987 M
t1 = 30s
t2 = 70s

∆M = M2 - M1 = 0.00987 M - 0.678 M = -0.66813 M

∆t = t2 - t1 = 70s - 30s = 40s

r = ∆M/∆t = -0.66813 M / 40s ≈ -0.0167 M/s

Therefore, the constant rate in this example is approximately -0.0167 M/s.

To find the constant rate, you need to calculate the change in molarity over the change in time.

Step 1: Calculate the change in molarity: Subtract the initial molarity from the final molarity.

Change in Molarity = Final Molarity - Initial Molarity

Step 2: Calculate the change in time: Subtract the initial time from the final time.

Change in Time = Final Time - Initial Time

Step 3: Divide the change in molarity by the change in time to find the constant rate.

Constant Rate = Change in Molarity / Change in Time

Let's go through the calculations:

Change in Molarity = 0.00987 M - 0.678 M = -0.66813 M
Change in Time = 70 s - 30 s = 40 s

Constant Rate = -0.66813 M / 40 s ≈ -0.0167 M/s

Therefore, the constant rate for this example is approximately -0.0167 M/s.