Fe2O3 + 2Al --> 2Fe + Al2O3
How many grams of Fe will form when 97.6g Al2O3 form?
Please & Thank you
To answer this question, we can use the stoichiometry of the balanced chemical equation provided.
Given:
- Balanced chemical equation: Fe2O3 + 2Al → 2Fe + Al2O3
- Grams of Al2O3 formed: 97.6 g
First, we need to calculate the molar mass of Al2O3:
- The molar mass of Al = 26.98 g/mol
- The molar mass of O = 16.00 g/mol (there are 3 O atoms in Al2O3)
- Total molar mass of Al2O3 = (2 * molar mass of Al) + (3 * molar mass of O)
= (2 * 26.98 g/mol) + (3 * 16.00 g/mol)
= 101.96 g/mol
Next, we need to calculate the moles of Al2O3 formed:
- Moles of Al2O3 = mass of Al2O3 / molar mass of Al2O3
= 97.6 g / 101.96 g/mol
≈ 0.956 mol
Using the stoichiometry of the balanced chemical equation, we can determine the moles of Fe formed:
- From the balanced chemical equation, we see that the molar ratio between Al2O3 and Fe is 1:2. This means that for every 1 mol of Al2O3, 2 mol of Fe is formed.
- Moles of Fe = (moles of Al2O3) * (2 mol Fe / 1 mol Al2O3)
= 0.956 mol * (2 mol Fe / 1 mol Al2O3)
= 1.912 mol
Finally, we can calculate the grams of Fe formed:
- Grams of Fe = (moles of Fe) * (molar mass of Fe)
= 1.912 mol * (55.85 g/mol)
≈ 106.77 g
Therefore, approximately 106.77 grams of Fe will be formed when 97.6 grams of Al2O3 react.
To find out how many grams of Fe will form when 97.6g of Al2O3 reacts, we can use stoichiometry.
First, we need to determine the molar mass of Al2O3 (aluminum oxide) and Fe:
- The molar mass of Al2O3 is 101.96 g/mol (aluminum: 26.98 g/mol, oxygen: 16.00 g/mol x 3).
- The molar mass of Fe is 55.85 g/mol.
Next, we can set up a stoichiometric ratio using the balanced chemical equation:
2Al : 2Fe : 1Al2O3
Since the ratio of Al to Al2O3 is 2:1, we can calculate the number of moles of Al2O3:
moles of Al2O3 = mass of Al2O3 / molar mass of Al2O3
moles of Al2O3 = 97.6g / 101.96 g/mol
Now, we can use the stoichiometric ratio to find the moles of Fe. From the balanced equation, we can see that 1 mole of Al2O3 reacts to form 2 moles of Fe:
moles of Fe = moles of Al2O3 x (2 moles of Fe / 1 mole of Al2O3)
Finally, we can convert moles of Fe to grams of Fe using the molar mass of Fe:
grams of Fe = moles of Fe x molar mass of Fe
Plug in the values and calculate to find the answer.
This is worked exactly the same way as the one I did previously.
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