A dilute sulfuric acid solution that is 3.39 molality H2SO4 has a density of 1.18 g/mL. How many moles of H2SO4 are there in 375 mL of this solution?

3.39 m = 3.39 moles (332.22 g) + 1 kg solvent.

Mass of solution = 332.22g + 1,000g = 1332.22 grams.

375 mL has a mass of what?
mass = volume x density = 375 mL x 1.18 g/mL = 442.5 grams.

g solute in 375 mL = 332.22g x (442.5/1332.22) = 110.35 g which is 110.35/98 = 1.126 moles H2SO4.

Does that sound reasonable? How much solvent do we have in that 442.5 g. That will be 442.5-110.35 = 332.15 g
and 1.126 mole/0.33215 kg = 3.39 m so I think it is reasonable.

A couple of things I forgot to mention.

1. I used 98 for the molar mass of H2SO4. That may not be close enough for you so you need to through the calculations and adjust numbers as appropriate.
2. I used too many significant figures and you need to adjust them. The final answer should have no more than 3.

To determine the number of moles of H2SO4 in 375 mL of a solution, we need to use the given information about the molality and density of the solution.

Molality (m) is defined as the number of moles of solute per kilogram of solvent. In this case, we are given that the solution has a molality of 3.39 molality H2SO4. This means that for every kilogram of solution, there are 3.39 moles of H2SO4.

To calculate the number of moles of H2SO4 in 375 mL of the solution, we first need to convert the volume of the solution to kilograms. To do this, we need to know the mass of the solution.

The density of the solution is given as 1.18 g/mL. This means that 1 mL of the solution has a mass of 1.18 grams. To find the mass of 375 mL of the solution, we can multiply the volume by the density:

Mass (in grams) = Volume (in mL) * Density (in g/mL)
Mass = 375 mL * 1.18 g/mL = 442.5 grams.

Now, we need to convert the mass of the solution to kilograms:

Mass (in kg) = Mass (in grams) / 1000
Mass in kg = 442.5 g / 1000 = 0.4425 kg.

Now that we have the mass of the solution in kilograms, we can calculate the number of moles of H2SO4 in the solution:

Number of moles = Molality * Mass (in kg)
Number of moles = 3.39 molality H2SO4 * 0.4425 kg = 1.499275 moles.

Therefore, there are approximately 1.499275 moles of H2SO4 in 375 mL of the solution.