Express the function F(x)=1/(x+9) in the form g of h. If h(x)= x+9 , find the function g(x).

Well, I hope you're ready to clown around because it's time for some function fun!

Let's start by expressing the function F(x) = 1/(x+9) in the form g(h). We know that h(x) = x+9, so it's time to find the function g(x).

To do this, let's substitute x+9 into F(x). So, g(x) = F(h(x)).

Let's plug in h(x) into F(x):

F(h(x)) = 1/(h(x) + 9)

Since h(x) = x+9, we can substitute it into our equation:

F(h(x)) = 1/((x+9) + 9)

Simplifying further:

F(h(x)) = 1/(x+18)

Voila! The function g(x) is g(x) = 1/(x+18).

Now giddy up and go have fun with that function!

To express the function F(x) = 1/(x+9) in the form g o h, we need to find a function g(x) that when applied to h(x) = x+9, produces F(x).

Let's start by considering the expression F(x) = 1/(x+9). To simplify this, we can let h(x) = x+9. This means that when we apply the function g(x) to h(x), it should result in F(x).

Applying the function g(x) to h(x) = x+9, we get:

g(h(x)) = g(x+9)

Now, we want g(h(x)) = F(x), so let's find g(x) for this to be true.

Substituting g(x) into the equation g(h(x)) = F(x), we have:

g(x+9) = F(x) = 1/(x+9)

Therefore, the function g(x) that satisfies this condition is g(x) = 1/x.

To express the function F(x) = 1/(x+9) in the form g of h, we need to rewrite it using the given function h(x) = x+9.

Let's start by substituting the expression for h(x) into F(x):

F(x) = 1/(h(x))
= 1/(x+9)

Now, we need to find the function g(x) such that F(x) = g(h(x)).

Since F(x) = 1/(x+9), we can rewrite it as:

F(x) = g(h(x))
= g(x+9)

Therefore, the function g(x) that corresponds to F(x) = 1/(x+9) is g(x) = 1/x.

Given g o h(x) = g(h(x)) = 1/(x+9)

and h(x) = x+9

g(h(x)) = 1/(x+9)
g(x+9) = 1/(x+9)
g(y) = 1/y, or
g(x) = 1/x

Let f(x)=1/x+9 and h(x)= 1/ x-9 find