A crate full of artichokes rests on a ramp that is inclined 10.0° above the horizontal. Give the direction of the normal force and the friction force acting on the crate in each of these situations.
(a) The crate is at rest.
Normal Force :
1.perpendicular to and away from the ramp
2.perpendicular to and into the ramp
3.along the ramp upward
4.along the ramp downward
Friction force :
1.perpendicular to and away from the ramp
2.perpendicular to and into the ramp
3.along the ramp upward
4.along the ramp downward
(b) The crate is being pushed and is sliding up the ramp.
Normal Force :
1.perpendicular to and away from the ramp
2.perpendicular to and into the ramp
3.along the ramp upward
4.along the ramp downward
Friction force :
1.perpendicular to and away from the ramp
2.perpendicular to and into the ramp
3.along the ramp upward
4.along the ramp downward
(c) The crate is being pushed and is sliding down the ramp.
Normal Force :
1.perpendicular to and away from the ramp
2.perpendicular to and into the ramp
3.along the ramp upward
4.along the ramp downward
Friction force :
1.perpendicular to and away from the ramp
2.perpendicular to and into the ramp
3.along the ramp upward
4.along the ramp downward
Im guessing A is 1 and then 4, B is 2 and then 3, and C is 1 and then 4
Well, you are right on this...
B is 2
Everything else is wrong. I would review force diagrams in your text. Secondly: MEMORIZE THIS...friction always opposes motion.
Then would that mean A is 2 then 3, B is 2 then 4, and C is 2 then 3?
exactly
Wait wouldn't the normal force for C be perpendicular to and away from the ramp?
Normal force is the component of weight that is perpendicular to the plane. It would only be away from the ramp if the mass started flying upwards. In this case, artichokes don't fly, they slide downwards pressing some on the board (the normal component)
My teacher had said that all 3 normal forces were perpendicular and away from the ramp so idk
To determine the direction of the normal force and the friction force acting on the crate in each situation, we need to understand a few concepts.
1. Normal force: The normal force is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface.
2. Friction force: The friction force opposes the motion or tendency of motion between two surfaces in contact. It acts parallel to the surface and opposite to the direction of motion (or tendency of motion).
Now, let's analyze each situation:
(a) The crate is at rest.
In this case, since the crate is not moving, the normal force must balance the weight of the crate, keeping it in equilibrium. The normal force points perpendicular to and away from the ramp (option 1). The friction force counteracts any tendency of the crate to slide down the ramp, so it acts along the ramp and upward (option 3).
So, the answer for situation (a) is:
Normal force: Perpendicular to and away from the ramp (option 1)
Friction force: Along the ramp upward (option 3)
(b) The crate is being pushed and is sliding up the ramp.
When the crate is sliding up the ramp, it experiences a component of its weight pulling it down the ramp, so the normal force is reduced. Therefore, the normal force points perpendicular to and into the ramp (option 2). The friction force opposes the sliding motion, acting along the ramp but in the opposite direction (opposite to the motion), so it is along the ramp downward (option 4).
So, the answer for situation (b) is:
Normal force: Perpendicular to and into the ramp (option 2)
Friction force: Along the ramp downward (option 4)
(c) The crate is being pushed and is sliding down the ramp.
When the crate is sliding down the ramp, the normal force is increased to counterbalance the increased weight component acting against it. Therefore, the normal force points perpendicular to and away from the ramp (option 1). The friction force opposes the sliding motion, acting along the ramp but in the opposite direction (opposite to the motion), so it is along the ramp upward (option 3).
So, the answer for situation (c) is:
Normal force: Perpendicular to and away from the ramp (option 1)
Friction force: Along the ramp upward (option 3)
Therefore, your initial guesses were mostly correct. Situations (a), (b), and (c) correspond to options 1 and 4, 2 and 3, and 1 and 4 respectively.