a uniquw type of baskettball is played on the planet zarth. During the game a plyer flies above the basket and drops the ball in from a height of 10m. IF the ball takes 5.0 s to fall find the acceleration due to gravity on zarth.
Im just taking a guess but 2 miles?
d=1/2 a t^2 solve for a.
wheres your quiston?
To find the acceleration due to gravity on the planet Zarth, we can use the kinematic equation for vertical motion:
h = (1/2) * g * t^2
where
h is the height (10 m in this case),
g is the acceleration due to gravity on Zarth (what we want to find), and
t is the time taken for the ball to fall (5.0 s in this case).
Rearranging the equation to solve for g, we get:
g = (2 * h) / t^2
Plugging in the values, we have:
g = (2 * 10 m) / (5.0 s)^2
Calculating the expression on the right side gives:
g = 2 * 10 m / 25 s^2
g = 0.8 m/s^2
Therefore, the acceleration due to gravity on the planet Zarth is 0.8 m/s^2.