If 5.00 mL of HCl require 4.59 mL of 0.9581 M NaOH to just consume the HCl, what is the concentration of the HCl?
.9581*4.59=X then X/5 = .8795 which is the concentration
Write the equation, and see it is 1:1
HCl + NaOH ==> NaCl + HOH
Since it is 1:1 (and ONLY then), you can use mL x M = mL x M. Solve for the one unknown.
Germanium-69 has a half-life of 1.6 days. What fractions of atoms in a germanium-69 sample will remain in an undecayed state after the following? 4.8 days?
To determine the concentration of HCl, you can use the concept of stoichiometry. In this case, the reaction between HCl and NaOH is a 1:1 ratio, meaning that it requires equal amounts of HCl and NaOH to react completely.
Given that 5.00 mL of HCl reacts with 4.59 mL of 0.9581 M NaOH, we can use the following equation to find the concentration of HCl:
HCl + NaOH → NaCl + H2O
First, convert the mL of NaOH solution to moles:
moles of NaOH = volume (L) × molarity (mol/L)
moles of NaOH = 4.59 mL × (1 L/1000 mL) × 0.9581 mol/L
Next, since the reaction ratio between HCl and NaOH is 1:1, the moles of NaOH consumed will be equal to the moles of HCl present in the HCl solution.
moles of HCl = moles of NaOH
Now, we can calculate the concentration of HCl:
concentration (M) = moles of HCl / volume (L)
concentration (M) = moles of NaOH / volume (L)
Remember, the volume of HCl is given as 5.00 mL, which needs to be converted to liters:
volume (L) = 5.00 mL × (1 L/1000 mL)
Plug in the values:
concentration (M) = (4.59 mL × 0.9581 mol/L) / (5.00 mL × (1 L/1000 mL))
Now, calculate the concentration:
concentration (M) = 0.9581 mol/L × (4.59 mL/5.00 mL)
concentration (M) = 0.8796 mol/L
Therefore, the concentration of the HCl solution is 0.8796 M.