Without graphing, identify the slope and the y-intercept.

x-5/3=y/3
first you set it up as y=mx+b
-y/3=x+5/3

how do you get rid of the 3's?

Multiply all there things by 3/1.

-y= 3x+5

y= -3x-5

Ok I see how you worked it and I understand it but I have multiple choice as

a. slope= 5; y-intercept (0, 3)
c. Slope=-5; y-intercept (0, 3)
b. slope=3; y-intercept (0, -5)
d. slope=3; y-intercept (0, 5)
and the slope that you and I got is -3 with an intercept of (0, -5), but negative 3 is not an option what is wrong here?

To get rid of the 3's in the equation, you can multiply both sides of the equation by 3. This will cancel out the 3 in the denominator on the left side and eliminate the fraction.

Multiplying both sides of the equation by 3, we get:

3 * (-y/3) = 3 * (x + 5/3)

Simplifying further:

(-3y)/3 = 3x + (3 * 5)/3

Now, simplify the expression on each side:

-y = 3x + 5

Since we want to express the equation in slope-intercept form (y = mx + b), we need to isolate y on one side of the equation. Multiply both sides of the equation by -1 to change the sign of each term:

-(-y) = -(3x + 5)

y = -3x - 5

Now the equation is in the desired form, and we can easily identify the slope and y-intercept:

The slope (m) of this equation is -3, and the y-intercept (b) is -5.