# Math

Find an angle such that 3 times the complement of the angle is 10 degrees less than the supplement of the angle.

I know that supplement means 180 and complement is 90. I don't know what kind of problem this is.

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1. 3 (90-x)= (180-x) -10

270-3x= -1800+10x

2070=13x

Divide through by 13 and there it is. Translate what is given to something that you can use.

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buddy, you equation is right but the answer is wrong
that should be 50

(180-x)-10
should be
180-x-10

thanks buddy

buddy what is the the supplement of the angle if
its angle is greater than 3 times its compliment whose difference is 12 degree. which this angle is the diffrence of the complement and supplement is 152 degrees

thanks you buddies

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