Math

Find an angle such that 3 times the complement of the angle is 10 degrees less than the supplement of the angle.

I know that supplement means 180 and complement is 90. I don't know what kind of problem this is.

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  1. 3 (90-x)= (180-x) -10

    270-3x= -1800+10x

    2070=13x

    Divide through by 13 and there it is. Translate what is given to something that you can use.

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  2. at fiestadenoche

    buddy, you equation is right but the answer is wrong
    that should be 50

    (180-x)-10
    should be
    180-x-10

    thanks buddy

    buddy what is the the supplement of the angle if
    its angle is greater than 3 times its compliment whose difference is 12 degree. which this angle is the diffrence of the complement and supplement is 152 degrees

    thanks you buddies

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