A student placed 14.0g of glucose (C6H1206) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 35.0-mL sample of this glucose solution was diluted to 0.500mL . How many grams of glucose are in 100mL. of the final solution?

See below.

To determine the number of grams of glucose in 100 mL of the final solution, we need to use the information given about the dilution process.

First, let's calculate the concentration of the glucose solution.

We have 14.0 grams of glucose dissolved in the volumetric flask, which contains 100 mL of solution. Thus, the concentration of the glucose solution is:

Concentration of glucose solution = mass of glucose / volume of solution
Concentration = 14.0 g / 100 mL

Now, let's determine the concentration of the diluted solution.

We are given that a 35.0 mL sample of this glucose solution is diluted to 0.500 mL. This means the final solution is 0.500 mL in volume.

To calculate the concentration of the diluted solution, we can use the formula:

Concentration1 x Volume1 = Concentration2 x Volume2

Where:
Concentration1 is the initial concentration of the solution
Volume1 is the initial volume of the solution
Concentration2 is the final concentration of the solution
Volume2 is the final volume of the solution

In this case, we can rearrange the formula to solve for Concentration2:

Concentration2 = (Concentration1 x Volume1) / Volume2

Plugging in the values:
Concentration2 = (14.0 g / 100 mL) x 35.0 mL / 0.500 mL

Now that we have the concentration of the diluted solution, we can calculate the grams of glucose in 100 mL of the final solution:

Grams of glucose = Concentration2 x Volume2

Plugging in the values:
Grams of glucose = [(14.0 g / 100 mL) x 35.0 mL / 0.500 mL] x 100 mL

Simplifying the equation:
Grams of glucose = [(14.0 g / 0.500 mL) x 35.0 mL] x 100 mL

Finally, we can calculate the answer:

Grams of glucose = [(14.0 g / 0.500 mL) x 35.0 mL] x 100 mL
= (28.0 g/mL) x 3500 mL
= 98,000 g

Therefore, there are 98,000 grams of glucose in 100 mL of the final solution.