In 1995, the life expectancy of males in acertain country was 67.5 years. In 2002, it was 70.8 years. Let E represent the life expectancy in year t and let t represent the number of years since 1995. The linear function E(t) that fits the data is E(t)=?t+?. Use the function to predict the life expectncy of males in 2003. E(8)=

To find the linear function that fits the data, we can use the slope-intercept form of a linear equation: y = mx + b, where y is the dependent variable (life expectancy), x is the independent variable (number of years since 1995), m is the slope, and b is the y-intercept.

Given the information:
In 1995 (t = 0), the life expectancy was 67.5 years (E = 67.5).
In 2002 (t = 7), the life expectancy was 70.8 years (E = 70.8).

Using these two points, we can find the slope (m) of the linear function:
m = (E2 - E1) / (t2 - t1)
m = (70.8 - 67.5) / (7 - 0)
m = 3.3 / 7
m = 0.4714 (rounded to four decimal places).

Now, let's find the y-intercept (b) by substituting one of the points into the equation:
67.5 = 0.4714 * 0 + b
67.5 = b

So, the linear function E(t) that fits the data is E(t) = 0.4714t + 67.5.

To predict the life expectancy of males in 2003 (t = 8), we can substitute t = 8 into the equation:
E(8) = 0.4714 * 8 + 67.5
E(8) = 3.7712 + 67.5
E(8) ≈ 71.2712

Therefore, the predicted life expectancy of males in 2003 is approximately 71.2712 years.

To find the linear function that fits the given data, we need to calculate the slope and the y-intercept.

Given information:
E(0) = 67.5 (Life expectancy in 1995)
E(7) = 70.8 (Life expectancy in 2002)

First, we calculate the slope of the linear function:
Slope (m) = (E(7) - E(0)) / (7 - 0)
= (70.8 - 67.5) / 7
= 3.3 / 7
= 0.471

Next, we need to find the y-intercept (b).
We can use the equation: E(t) = m*t + b
Using one of the given data points (E(0) = 67.5):
67.5 = 0.471 * 0 + b
b = 67.5

Now we have the slope (m = 0.471) and the y-intercept (b = 67.5).
The linear function E(t) is:
E(t) = 0.471t + 67.5

To predict the life expectancy in 2003 (t = 8), we substitute t = 8 into the function:
E(8) = 0.471 * 8 + 67.5
E(8) = 3.768 + 67.5
E(8) = 71.268

Therefore, the predicted life expectancy for males in 2003 is 71.268 years.