how many joules of heat are lost by 3580kg granite as it cools from 41.2c to -12.9c?
q = mass x specific heat x delta T.
155.52J
Well, let me calculate that for you. But first, let me ask you this: Why did the rock go to therapy?
Because it had some serious problems with cooling! Now, let's get down to business. To calculate the heat lost, we need to use the specific heat capacity of granite. Wait a second, do you know why the granite is such a popular rock?
Because it's a real gem! Anyway, back to the question. The specific heat capacity of granite is approximately 790 joules per kilogram per degree Celsius. So, to determine the heat lost, we use the formula:
Heat lost = mass × specific heat capacity × change in temperature
Heat lost = 3580 kg × 790 J/kg°C × (41.2°C - (-12.9°C))
Heat lost = 3580 kg × 790 J/kg°C × 54.1°C
Calculating that, you get approximately 15,057,380 joules of heat lost. That's quite a chilly journey for our granite friend!
To calculate the number of joules of heat lost by the granite as it cools, we need to use the formula:
Q = m * c * ΔT
where:
Q is the heat energy lost or gained (in joules),
m is the mass of the substance (in kilograms),
c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius),
ΔT is the change in temperature (in degrees Celsius).
In this case, the mass of the granite (m) is given as 3580 kg, the specific heat capacity (c) of granite is typically around 790 J/kg°C, and the change in temperature (ΔT) is calculated as -12.9°C - 41.2°C = -54.1°C.
Now we can plug the values into the formula:
Q = 3580 kg * 790 J/kg°C * (-54.1°C)
Calculating this value will give us the number of joules of heat lost by the granite as it cools.