When 0.678 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 11.0C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
The molar heat of reaction, H rxn, for the reaction of
Ca(s) + 2H+(aq) -> Ca2+(aq) + H2(g)
THANKS! :)
I know that the start of the problem is this (I think):
-delta H = [(200)(4.184)(11.0)(1/1000)]/[(0.678/?)]
I just don't understand what the ? should be...Thanks!