How do i go about finding the integers of a product and quotient ... like, product of -20 whose quotient is -5 ..... thanks again
You divide the product by the quotient. So for instance, the answer for the above question will be 4. (positive 4) Since, Negative divided by negative is positive. Hope this helps.
Thank you Miss Rose!
x * y = -20
x/y = -5
-5y^2 = -20
y = 2
x = -10
You could also have y = -2 with x = 10
To find the integers of a product and quotient given certain conditions, such as the product of -20 and a quotient of -5, you can use basic algebraic equations. Here's how you can approach it:
Let's assume the first integer (a) is the product and the second integer (b) is the quotient.
1. Product: The product of two integers can be found by multiplying them. In this case, the product is -20. So, you can write the equation as: a * b = -20.
2. Quotient: The quotient of two integers can be found by dividing them. Here, the quotient is -5. So, you can write the equation as: a / b = -5.
To find the values of 'a' and 'b' that satisfy both conditions simultaneously, you can rearrange the second equation to solve for 'a' in terms of 'b':
a = -5b
Now, substitute this expression for 'a' in the first equation:
-5b * b = -20
Simplify the equation:
-5b^2 = -20
Divide both sides of the equation by -5:
b^2 = 4
Take the square root of both sides (remembering that the square root can be positive or negative):
b = ±2
Now substitute the values of 'b' back into the equation a = -5b:
For b = 2:
a = -5(2) = -10
For b = -2:
a = -5(-2) = 10
So, the two pairs of integers that satisfy the conditions are (-10, 2) and (10, -2).
Therefore, the product of -20 whose quotient is -5 can be expressed as either (-10, 2) or (10, -2).