is there no solution for a triangle with C=50deg
a=25 c=22?
Try the law of sines:
22/Sin50=25/SinA
A=60.5 deg
which leaves 180-60.5-50=69.48 deg
I don't see a problem.
a=25 c=22?
22/Sin50=25/SinA
A=60.5 deg
which leaves 180-60.5-50=69.48 deg
I don't see a problem.