Mr.Lin gave $3600 to his wife and kids. His wife got $500 more than the first child. The second child got half of what the first child got, how much did the first child receive?
W+F+S=3600
W-500=F
S=1/2 F
W+F+S=3600
W+W-500 +1/2 (W-500)=3600
solve.
THE WIFE GOT 1740 THE FIRST CHILD GOT 1240 N THE SECOND CHILD GOT 620
Let's solve this problem step by step:
Step 1: Set up equations
Let's assume that the amount the first child received is x dollars.
According to the problem, the wife received $500 more than the first child, so the amount the wife received would be x + $500.
The second child received half of what the first child received, so the amount the second child received would be (1/2)x.
Step 2: Write the equation
The total amount that Mr. Lin gave to his wife and kids is $3600. So, we can write the equation:
x + (x + $500) + (1/2)x = $3600
Step 3: Simplify the equation
Combining like terms, we get:
(2 1/2)x + $500 = $3600
Step 4: Solve for x
Subtract $500 from both sides of the equation:
(2 1/2)x = $3600 - $500
(2 1/2)x = $3100
To simplify the equation, convert the mixed number to an improper fraction:
(2 1/2)x = (5/2)x = $3100
Now, divide both sides of the equation by (5/2) to solve for x:
x = ($3100) / (5/2)
x = ($3100) * (2/5)
x = $1240
Therefore, the first child received $1240.