A potential difference of 0.90 V exists from one side to the other side of a cell membrane that is 5.0 NM thick. What is the electric field across the membrane?

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Thank You.

e=45.789

To find the electric field across the membrane, we can use the formula:

Electric field (E) = Potential difference (V) / Distance (d)

In this case, the potential difference (V) is given as 0.90 V, and the distance (d) is given as 5.0 nm.

Before we use the formula, we need to ensure that the units are consistent. The distance is given in nanometers (nm). However, it's more convenient to work with SI units, so we need to convert the distance to meters.

1 meter = 10^9 nanometers

Converting the distance from nanometers to meters:

5.0 nm = 5.0 x 10^(-9) m

Now, let's substitute the values into the formula:

E = 0.90 V / 5.0 x 10^(-9) m

Calculating this expression will give us the electric field across the membrane.