1. 3y=13divided by 2=>y=

2. 6divided by 15=12divided by y =>y=

3. 8 divided by 5 y - 4 = 20 =>y =

4. 3:8= y:32 =>y=

1. To find y in the equation 3y = 13 divided by 2, you need to isolate y on one side of the equation.

Solution:
Start with the equation 3y = 13 divided by 2.
To undo the multiplication of y by 3, you can divide both sides of the equation by 3. This will give:
(3y) / 3 = (13 / 2) / 3.
Simplifying further, you get:
y = (13 / 2) / 3.

So y = 13 / 2 divided by 3.

2. In the equation 6 divided by 15 = 12 divided by y, you need to find the value of y.

Solution:
Start with the equation 6 / 15 = 12 / y.
To solve this equation for y, you can cross multiply. This means multiplying the numerator of the left side with the denominator of the right side and vice versa.
You get:
(6)(y) = (15)(12).
Simplifying further:
6y = 180.
To isolate y, divide both sides of the equation by 6. This gives:
y = 180 / 6.

So y = 30.

3. In the equation 8 divided by 5y - 4 = 20, you need to find the value of y.

Solution:
Start with the equation 8 / (5y - 4) = 20.
To solve this equation for y, you should first remove the denominator by multiplying both sides of the equation by (5y - 4). This leads to:
8 = 20(5y - 4).
Distribute 20 to both terms inside the parenthesis:
8 = 100y - 80.
To isolate y, you need to move the constant term (-80) to the other side of the equation by adding 80 to both sides:
8 + 80 = 100y.
88 = 100y.
Divide both sides of the equation by 100 to solve for y:
y = 88 / 100.

So y = 0.88.

4. In the equation 3:8 = y:32, you need to find the value of y.

Solution:
To solve a proportion like this, you can use cross multiplication. This means multiplying the numerator of the first ratio with the denominator of the second ratio and vice versa.
You get:
(3)(32) = (8)(y).
96 = 8y.
To isolate y, divide both sides of the equation by 8:
96 / 8 = y.

So y = 12.