A train is travelling 20metres per second, accelerates at 0,5 cubic metres per second for 30 seconds.How far will it travel in this time?
To find the distance that the train will travel in this time, we can use the equation for motion with constant acceleration. The equation is:
d = ut + (1/2)at^2
Where:
d = distance
u = initial velocity
t = time
a = acceleration
In this case:
u = 20 m/s (initial velocity of the train)
t = 30 seconds (time)
a = 0.5 m/s^2 (acceleration)
Substituting the given values into the equation:
d = (20 m/s)(30 s) + (1/2)(0.5 m/s^2)(30 s)^2
First, we calculate the product of the initial velocity and time: 20 m/s * 30 s = 600 m.
Next, we calculate the product of (1/2)*(0.5 m/s^2)*(30 s)^2 = 1/2 * 0.5 * 900 = 225 m.
Finally, we add the two results together:
d = 600 m + 225 m = 825 m
Therefore, the train will travel a distance of 825 meters in 30 seconds.