Two aqueous solutions of sucrose, C12H22O12, are mixed. One solution is 0.1495 M sucrose and has d = 1.018 g/mL; the other is 12.00 sucrose by mass and has d = 1.038 g/ml.
Calculate the moles C12H22O12 percent in the mixed solution.
Please provide steps
(assume volume is same for both solns)
12.00 What?
To calculate the moles of C12H22O12 percent in the mixed solution, we need to determine the number of moles of C12H22O12 in each solution individually and then add them up.
Here are the steps:
Step 1: Calculate the mass of sucrose in each solution.
Mass = density x volume
For the first solution:
Mass of sucrose in solution 1 = density x volume of solution 1
For the second solution:
Mass of sucrose in solution 2 = density x volume of solution 2
Since the volume is assumed to be the same for both solutions, we can skip calculating the volume separately.
Step 2: Calculate the moles of sucrose in each solution.
Moles = mass / molar mass
The molar mass of sucrose (C12H22O12) can be calculated by adding the atomic masses of all the elements in the compound.
Step 3: Calculate the total moles of sucrose in the mixed solution.
Total moles = Moles in solution 1 + Moles in solution 2
Step 4: Calculate the moles C12H22O12 percent in the mixed solution.
Moles C12H22O12 percent in the mixed solution = (Total moles / Total volume) x 100
Remember to convert the density from g/mL to g/cm³, if necessary, to ensure units are consistent.
That's it! By following these steps, you can calculate the moles C12H22O12 percent in the mixed solution.