You are asked to prepare 150.0 mL of 3.15×10−2 M AgNO3.
2.) An aqueous solution is 6.40% methanol CH3OH by mass, with d = 0.988 g/mL}
What is the molarity of CH3OHOH} in this solution?
Didn't I show you how to do this last night? I think so.
To determine the molarity of CH3OH in the given solution, we first need to determine the number of moles of CH3OH in the solution, and then divide it by the volume of the solution in liters.
To calculate the moles of CH3OH, we first need to calculate the mass of CH3OH in the solution. We know that the solution is 6.40% methanol CH3OH by mass, and we are given the density of the solution as 0.988 g/mL.
Step 1: Calculate the mass of the solution.
We are given the volume of the solution as 150.0 mL. Using the density, we can calculate the mass of the solution as follows:
Mass of solution = Volume of solution x Density
Mass of solution = 150.0 mL x 0.988 g/mL
Step 2: Calculate the mass of CH3OH in the solution.
Since the solution is 6.40% methanol by mass, we can calculate the mass of CH3OH as follows:
Mass of CH3OH = 6.40% x Mass of solution
Step 3: Calculate the moles of CH3OH.
To calculate the moles of CH3OH, we need to divide the mass of CH3OH by its molar mass. The molar mass of CH3OH is 32.04 g/mol.
Moles of CH3OH = Mass of CH3OH / Molar mass of CH3OH
Step 4: Calculate the molarity of CH3OH.
Finally, to calculate the molarity of CH3OH, we divide the moles of CH3OH by the volume of the solution in liters.
Molarity of CH3OH = Moles of CH3OH / Volume of solution (in liters)
By following these steps, you should be able to calculate the molarity of CH3OH in the given solution.