A swimmer runs horizontally off a diving board with a speed of 3.14 m/s and hits the water a horizontal distance of 2.16 m from the end of the board. How high above the water was the diving board?

How long did it take to hit the water?

time= 2.16/3.14 seconds

hf=ho- 1/2 g t^2
0=ho-4.9 t^2 solve for ho,knowing t

Well, it sounds like this swimmer wanted to make a big splash! To figure out the height of the diving board, we can use the horizontal distance the swimmer traveled and their initial horizontal speed.

Now, let me take a wild guess and assume that the diving board wasn't doing any tricks or bouncing up and down like a trampoline. In that case, we can neglect any vertical velocity.

So, we have the horizontal distance traveled (2.16 m) and the horizontal speed (3.14 m/s). Since time is constant in this horizontal motion, we can use the equation:

horizontal distance = horizontal speed x time

Solving for time, we get:

time = horizontal distance / horizontal speed

Now, if we assume that the diving board is at a certain height (let's call it 'h'), the time it takes for the swimmer to travel that 2.16 m horizontally also tells us how long they were in the air vertically.

With that information, we can use the equation for uniform motion in the vertical direction:

vertical displacement = (1/2) x acceleration x time^2

But hold on a second, the acceleration in the vertical direction is the acceleration due to gravity, which is approximately 9.8 m/s^2. So we can rewrite the equation as:

vertical displacement = (1/2) x (9.8 m/s^2) x time^2

Remember, time is the same as we got from the horizontal motion. Now, here's where things get interesting - the vertical displacement is actually equal to the height of the diving board. So we can rewrite the equation again:

height = (1/2) x (9.8 m/s^2) x time^2

Now, substituting the value of time we got, we can calculate the height of the diving board.

I could give you the exact numerical answer using all these fancy equations, but I think I'll leave that to a not-so-funny calculator. The important thing is that you can solve it using these steps. Good luck!

To find the height of the diving board above the water, we can use the equation for the horizontal distance traveled by an object in projectile motion:

d = v₀x * t

Where:
d is the horizontal distance traveled (2.16 m),
v₀x is the horizontal component of the initial velocity (3.14 m/s), and
t is the time of flight.

We can rearrange the equation to solve for time:

t = d / v₀x

Substituting the given values:

t = 2.16 m / 3.14 m/s
t ≈ 0.688 m

Now, we can use the equation for the vertical displacement in projectile motion to find the height:

y = v₀y * t + (1/2) * g * t²

Where:
y is the vertical displacement,
v₀y is the vertical component of the initial velocity (the initial velocity is perpendicular to the board, so v₀y = 0), and
g is the acceleration due to gravity (assumed to be -9.8 m/s²).

Simplifying the equation:

y = 0 + (1/2) * (-9.8 m/s²) * (0.688 m)²
y ≈ -2.57 m²/s²

Since height cannot be negative, we take the absolute value:

height of the diving board = |y| ≈ 2.57 m

Therefore, the diving board was approximately 2.57 meters above the water.

To find the height of the diving board above the water, we can use the principles of projectile motion. We assume that the motion is in two dimensions, horizontally and vertically.

First, we need to determine the time it takes for the swimmer to hit the water. We can use the horizontal velocity and distance traveled to find the time.

The horizontal distance traveled is given as 2.16 m, and the horizontal velocity is 3.14 m/s. We can use the equation:

distance = velocity × time

So, 2.16 m = 3.14 m/s × time

Solving for time, we divide both sides of the equation by 3.14 m/s:

time = 2.16 m / 3.14 m/s

time ≈ 0.688 s

Now, to find the height, we need to consider the vertical motion. We can use the formula for vertical displacement:

displacement = initial velocity × time + (1/2) acceleration × time^2

Since the swimmer starts from rest vertically, the initial velocity is 0. The acceleration can be taken as the acceleration due to gravity, approximately 9.8 m/s^2.

The displacement is the height we want to find. We can rearrange the equation to solve for it:

displacement = (1/2) acceleration × time^2

Substituting the known values:

displacement = (0.5) × 9.8 m/s^2 × (0.688 s)^2

displacement ≈ 2.42 m

Therefore, the height of the diving board above the water is approximately 2.42 meters.