A race car traveling at +44m/s is accelerated to a velocity of +22 m/s over an 11 s interval. What is the displacement during this time?
33/11 see below
I mean 33*11, speed times distance
To find the displacement during this time, we can use the equation:
displacement = (final velocity - initial velocity) x time
Given:
Initial velocity (u) = +44 m/s
Final velocity (v) = +22 m/s
Time (t) = 11 s
Substituting the values into the equation:
displacement = (+22 m/s - +44 m/s) x 11 s
Simplifying the equation:
displacement = (-22 m/s) x 11 s
The negative sign indicates that the car is decelerating.
Now, we can calculate the displacement:
displacement = -242 m
Therefore, over this 11 second interval, the car has a displacement of -242 meters.
v = Vi + a t
22 = 44 + 11 a
a = -22/11
x = Xi + Vi t +(1/2) a t^2
x-Xi = 44 (11) +(1/2)(-22/11)(11)^2
= (11)(44-11)
= 33(11)