A 10.0% by mass H2SO4(aq) solution has a density of 1.07 g·cm-3.

How many milliliters of solution contain 8.34 g of H2SO4?

What mass (in grams) of H2SO4 is in 248 mL of solution?

It's been a while since I have had a chem class...so sorry if this seems really easy I just don't understand how to find it...

77.93 is not right.

Annon had it right.
mass = volume x density
8.34g = volume x 1.07 g/mL
volume = 8.34/1.07 = 7.79 mL.

Okay... I think this might help... but I'm really not sure either.

density=mass/volume
cm3=mL

1.volume=mass/density=8.34g/(1.07g/mL)=7.79mL

2.mass=density*volume=1.07*248=265.36g.

Here's where I'm confused. Do we have to multiply these two answers by .1 because it's 10% H2SO4 by mass? If that's the case, you can probably take it from here. Hope this helps. Good luck.

I finally figured it out actually. And yes the .1 has to be multiplied in there. answers end up being 77.93 mL and 26.54g

Oh, chemistry, always finding ways to confuse us, right? Don't worry, I'm here to help you out with some clownish charm!

To solve these questions, we need to use the given information about the concentration and density of the solution. But fear not, I'll guide you through it with a touch of humor!

Question 1: How many milliliters of solution contain 8.34 g of H2SO4?

First, let's determine the mass of the solution. Since the density is given as 1.07 g/cm³, we can set up a simple equation:

Mass = Density × Volume

Let's say the volume of the solution is V ml. We can then write it as:

8.34 g = 1.07 g/cm³ × V ml

Now, the good news is that grams cancel out on both sides, leaving us with:

8.34 = 1.07 × V

And all we need to do is solve for V, which represents the volume in milliliters. So, divide both sides by 1.07:

V = 8.34 / 1.07

And there you have it, the volume of the solution in milliliters!

Question 2: What mass (in grams) of H2SO4 is in 248 mL of solution?

Similarly, let's use the same equation:

Mass = Density × Volume

This time, the volume is 248 mL. So we can write:

Mass = 1.07 g/cm³ × 248 mL

And just like before, we can simplify it:

Mass = 1.07 × 248

Multiply those numbers together and voila! You'll have the mass of H2SO4 in grams.

Remember, chemistry can be a bit tricky sometimes, but don't be afraid to ask for help. I'm here to clown around and make things a little lighter for you!

No problem! Let me help you with these questions step by step.

For the first question, you are given the mass of H2SO4 (8.34 g) and you need to find the volume of the solution in milliliters. Here's how to do it:

Step 1: Calculate the mass of the solution. Since the solution is 10.0% H2SO4 by mass, you can calculate the mass of the solution using the formula:

mass of solution = mass of H2SO4 / (percentage of H2SO4/100)

mass of solution = 8.34 g / (10.0/100) = 8.34 g / 0.1 = 83.4 g

Step 2: Use the density of the solution to find the volume. Density is defined as mass divided by volume, so you can rearrange the formula to calculate the volume:

density = mass / volume

volume = mass / density

volume = 83.4 g / 1.07 g·cm-3 = 77.94 cm3 (cubic centimeters)

Step 3: Convert cubic centimeters to milliliters. Since 1 cm3 is equal to 1 mL, the volume of the solution is also 77.94 mL.

Therefore, 8.34 g of H2SO4 is contained in 77.94 mL of the solution.

Now, let's move on to the second question.

For the second question, you are given the volume of the solution (248 mL) and you need to find the mass of H2SO4 in grams. Here's the step-by-step procedure:

Step 1: Use the density of the solution to calculate the mass of the solution:

mass of solution = volume of solution × density

mass of solution = 248 mL × 1.07 g·cm-3 = 265.36 g

Step 2: Calculate the mass of H2SO4 in the solution. Since the solution is 10.0% H2SO4 by mass, you can multiply the mass of the solution by the percentage of H2SO4:

mass of H2SO4 = mass of solution × (percentage of H2SO4/100)

mass of H2SO4 = 265.36 g × (10.0/100) = 26.536 g

Therefore, 248 mL of the solution contains 26.536 g of H2SO4.

I hope that helps you understand the process of solving these problems! Let me know if you have any further questions.