Based on the balanced equation
2Ba + O2 → 2BaO
calculate the number of BaO formula units formed when 54 Ba atoms and 21 O2 molecules react?
To calculate the number of BaO formula units formed, we need to use the coefficients in the balanced equation.
The coefficient in front of Ba is 2, which means that 2 moles of Ba are needed to react.
The coefficient in front of O2 is also 2, which means that 2 moles of O2 are needed to react.
1 mole of BaO is formed for every 2 moles of Ba that react. So, if 2 moles of Ba react, then 1 mole of BaO is formed.
Similarly, 1 mole of BaO is formed for every 2 moles of O2 that react. So, if 2 moles of O2 react, then 1 mole of BaO is formed.
To convert the given amounts of Ba and O2 into moles, we need to use their respective atomic masses. The atomic mass of Ba is 137.33 g/mol, and the atomic mass of O2 is 32.00 g/mol.
First, let's calculate the number of moles of Ba:
54 Ba atoms x (1 mol Ba / 6.022 x 10^23 Ba atoms) = 8.98 x 10^-23 moles of Ba
Next, let's calculate the number of moles of O2:
21 O2 molecules x (1 mol O2 / 6.022 x 10^23 O2 molecules) = 6.97 x 10^-23 moles of O2
Now, let's determine the limiting reactant. The moles ratio between Ba and O2 is 2:2, which means that they have an equal stoichiometric ratio. Therefore, the limiting reactant is determined by doing a comparison between the actual moles of Ba and O2.
Comparing the moles of Ba and O2:
8.98 x 10^-23 moles of Ba < 6.97 x 10^-23 moles of O2
Since the moles of Ba are smaller, it means that the Ba is the limiting reactant.
Now, let's calculate the number of moles of BaO formed. Since 2 moles of Ba react to form 1 mole of BaO, and we have determined that Ba is the limiting reactant, we can use the moles of Ba to calculate the moles of BaO:
8.98 x 10^-23 moles of Ba x (1 mol BaO / 2 mol Ba) = 4.49 x 10^-23 moles of BaO
Lastly, let's convert the moles of BaO into the number of BaO formula units using Avogadro's number (6.022 x 10^23 formula units/mol):
4.49 x 10^-23 moles of BaO x (6.022 x 10^23 formula units/mol) = 2.70 x 10^1 formula units of BaO
Therefore, when 54 Ba atoms and 21 O2 molecules react, we would expect to form approximately 2.70 x 10^1 (27) formula units of BaO.
To calculate the number of BaO formula units formed, we need to use the stoichiometry of the balanced equation. The balanced equation shows that 2 moles of Ba react with 1 mole of O2 to produce 2 moles of BaO.
First, let's convert the given quantities (54 Ba atoms and 21 O2 molecules) to moles.
1 mole of any element contains Avogadro's number of atoms or molecules. Avogadro's number is approximately 6.022 x 10^23.
Number of moles of Ba = Number of atoms / Avogadro's number
Number of moles of Ba = 54 / (6.022 x 10^23) = 8.97 x 10^-23 moles
Number of moles of O2 = Number of molecules / Avogadro's number
Number of moles of O2 = 21 / (6.022 x 10^23) = 3.49 x 10^-23 moles
Now, we can use the stoichiometry of the balanced equation to determine the number of moles of BaO produced:
From the balanced equation, we know that 2 moles of Ba react with 1 mole of O2 to produce 2 moles of BaO.
So, using the mole ratios:
Number of moles of BaO produced = (Number of moles of Ba) / 2
Number of moles of BaO produced = (8.97 x 10^-23) / 2 = 4.49 x 10^-23 moles
Finally, we convert the moles of BaO produced to formula units by multiplying by Avogadro's number:
Number of BaO formula units = (Number of moles of BaO) x Avogadro's number
Number of BaO formula units = (4.49 x 10^-23) x (6.022 x 10^23) = 2.70 x 10^1 formula units
Therefore, when 54 Ba atoms and 21 O2 molecules react, the number of BaO formula units formed is approximately 27.0 formula units.
I know I had Chemistry last year, but I'm not 100 percent sure about this answer: 21.
you need 2 atoms each of each element. Divide 54 by 2, so you get 27 Ba atoms in groups of 2. 21 is already 2 O atoms.
So you get 27 and 21. the smaller one is 21, which is the greatest amount you can get for 2BaO.
54 Ba atoms:
54 Ba atoms x (2 BaO molecules/2 Ba atoms) = 54 x 2/2 = 54 molecules(formula units) BaO.
21 O2 molecule:
21 O2 molecules x (2 BaO molecules/1 O2 molecule) = 42 BaO molecules.
Therefore, 42 BaO molecules will be the product formed. O2 is the limiting reagent.