I am having such a hard time in this class. Hopefully someone here can help me to understand some of what they are trying to teach me. I have a problem here and have been working on it for about an hour now and I can not figure it out. I need to come up with an answer but I need to understand it too so if someone helps me could you please break things down for me so that I learn. Thank you.

I have to subtract and then simplify if possible.

the problem is....

(4-v)over(v-6) minus (2v-5)over(6-v).

I hope I put that on there to where someone can understand it because I have a hard time trying to figure out how to even get them on a computer for some of my assignments.

(4-v)/(v-6) - (2v-5)/(6-v)

You can change the sign of the denominator of the second term and change the - to + at the same time.
That gives you
= (4-v)/(v-6) + (2v-5)/(v-6)
Now that you have a common denominator, you can add the numerators together.
= (4 - v + 2v -5)/(v-6)
= (v-1)/(v-6)

Sure, I can help you understand how to solve this problem step by step.

To subtract and simplify the expression (4-v)/(v-6) - (2v-5)/(6-v), we need to find a common denominator for the two fractions. The common denominator is obtained by multiplying the denominators of the fractions together.

The denominator of the first fraction is (v-6), and the denominator of the second fraction is (6-v). Notice that these two expressions are negatives of each other: (v-6) = -(6-v). Therefore, we can rewrite the problem as:

(4-v)/(v-6) - (2v-5)/-(v-6)

Now, we can simplify and combine the fractions. To do this, we will multiply each fraction by the appropriate factors to create a common denominator:

(4-v)/(v-6) * (-(v-6))/(-(v-6)) - (2v-5)/(-(v-6))

Simplifying the multiplication gives us:

-(4-v)(v-6)/(v-6)(v-6) - (2v-5)/(v-6)

Next, we can simplify the numerator:

-(4-v)(v-6) = -[(4-v)(v-6)] = -[4(v-6) - v(v-6)] = -[4v - 24 - v^2 + 6v]
= -[-v^2 + 10v - 24] = v^2 - 10v + 24

Using the distributive property, the expression becomes:

(v^2 - 10v + 24)/(v-6) - (2v-5)/(v-6)

Now, we combine the fractions by subtracting the numerators:

(v^2 - 10v + 24 - 2v + 5)/(v-6)

Simplifying further gives us:

(v^2 - 12v + 29)/(v-6)

Therefore, the simplified expression of (4-v)/(v-6) - (2v-5)/(6-v) is:

(v^2 - 12v + 29)/(v-6)

Now you have successfully subtracted and simplified the given expression.