A 893 g sample of a solution of the solute (CH3)2CO in the solvent C4H8O that has a concentration of 28.6 pph by mass (CH3)2CO is available. Calculate the amount (g) of acetone that is present in the sample.
Molar Mass (g/mol)
(CH3)2CO 58.05
C4H8O 72.12
Density (kg/m3):
(CH3)2CO 789.9
C4H8O 889.2
Name/Formula:
acetone
(CH3)2CO
tetrahydrofuran
C4H8O
Is that pph parts per hundred (the same as percent by mass) or is that a typo and you meant to type ppb (parts per billion).
it is parts per hundred
To calculate the amount of acetone present in the solution, we can use the following steps:
1. Convert the concentration from parts per hundred (pph) to mass fraction (mass %):
Mass fraction (mass %) = Concentration (pph) / 10
Mass fraction (mass %) = 28.6 / 10 = 2.86%
2. Determine the mass of the solute (acetone) in the solution:
Mass of solute (acetone) = Mass of solution × Mass fraction (mass %)
Mass of solution = 893 g (given)
Mass of solute (acetone) = 893 g × 2.86% = 25.58 g
Therefore, the amount of acetone present in the sample is 25.58 grams.