how many grams of propane are in a 35L container at 40 degrees and 900 torr?
Use PV = nRT to calculate n, then n = grams/molar mass to solve for grams. Don't forget to use Kelvin for T.
To determine the number of grams of propane in a 35L container at 40 degrees and 900 torr, we need to use the ideal gas law equation, which is as follows:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
First, we need to convert the given temperature from degrees Celsius to Kelvin. The Kelvin scale is obtained by adding 273.15 to the Celsius temperature.
So, 40 degrees Celsius + 273.15 = 313.15 Kelvin
Now, convert the pressure from torr to atm by dividing by 760 (since 1 atm = 760 torr).
900 torr / 760 torr/atm = 1.184 atm
Now we have all the values required to solve the equation. Rearranging the equation, we get:
n = PV / RT
n = (1.184 atm) * (35 L) / (0.0821 L·atm/mol·K) * (313.15 K)
Calculating the expression above will give us the number of moles of propane in the container.
Finally, to convert moles to grams, we need to know the molar mass of propane, which is 44.1 grams/mol.
To obtain the final result in grams, multiply the number of moles by the molar mass:
grams of propane = (number of moles) * (molar mass)