Find three consecutive integers such that 5 times the first and third is 14 greater than 8 times the second. Please show all work.
Let the first integer be N
5*[N + (N+2)] = 8(N+1) + 14
6N + 10 = 8N + 22
Now solve for N.
It will be a good exercise for you to do the remaining steps yourself.
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