Ammeter 1 reads 0.20 A.

a. What should ammeter 3 indicate?
b. What should ammeter 4 indicate?

Given:
RA = 22-OHM
RB = 13-OHM
A1 = 0.20 A

Ammeter 2 reads 0.15A.

a. Find the voltage across the 22-ohm resistor?
b. Find the voltage across the 15-ohm resistor?
c. What is the battery voltage?

Given:
RA = 22-OHM
RB = 15-OHM
A1 = 0.20 A
A2 = 0.15 A

Soon, the diagram will be posted, thanks a lot.

ok by the time, i can try and solve this problem.

R = RA + RB
R = 22-ohm + 15-ohm
R = 37-ohm

I = V source / RA + RB
But the voltage is not given.

To solve these problems, we need to use Ohm's law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across it divided by its resistance (R).

Let's start by analyzing Ammeter 1. We are given that Ammeter 1 reads 0.20 A. Ammeter 1 is connected in series with resistors RA and RB. Therefore, the current passing through Ammeter 1 should be the same as the current passing through both resistors.

Using Ohm's law, we can find the total resistance (RT) of the circuit:

RT = RA + RB
RT = 22 ohms + 13 ohms
RT = 35 ohms

Since we know the total resistance and the current passing through it, we can find the voltage across Ammeter 1 using Ohm's law:

V = I * R
V = 0.20 A * 35 ohms
V = 7 volts

a. What should ammeter 3 indicate?

Ammeter 3 is connected in parallel with resistor RA. In a parallel circuit, the voltage across all components is the same. Therefore, the voltage across Ammeter 3 should be the same as the voltage across resistor RA, which is 7 volts.

b. What should ammeter 4 indicate?

Ammeter 4 is connected in parallel with resistor RB. Again, the voltage across all components in parallel is the same. Therefore, the voltage across Ammeter 4 should be the same as the voltage across resistor RB, which is also 7 volts.

Now let's move on to analyzing Ammeter 2. We are given that Ammeter 2 reads 0.15 A. Ammeter 2 is connected in series with resistors RA and RB. Therefore, the current passing through Ammeter 2 should be the same as the current passing through both resistors.

Using Ohm's law, we can find the total resistance (RT) of the circuit:

RT = RA + RB
RT = 22 ohms + 15 ohms
RT = 37 ohms

Since we know the total resistance and the current passing through it, we can find the voltage across Ammeter 2 using Ohm's law:

V = I * R
V = 0.15 A * 37 ohms
V = 5.55 volts

a. Find the voltage across the 22-ohm resistor?

The voltage across the 22-ohm resistor is the same as the voltage across Ammeter 2, which is 5.55 volts.

b. Find the voltage across the 15-ohm resistor?

The voltage across the 15-ohm resistor is the same as the voltage across Ammeter 2, which is also 5.55 volts.

c. What is the battery voltage?

To find the battery voltage, we need to add up the voltages across the resistors. In this case, the battery voltage is equal to the sum of the voltage across the 22-ohm resistor and the voltage across the 15-ohm resistor:

Battery voltage = Voltage across 22-ohm resistor + Voltage across 15-ohm resistor
Battery voltage = 5.55 volts + 5.55 volts
Battery voltage = 11.10 volts