What volume ( L ) of the solute ethanol should be mixed with 0.546 L of the solvent C4H8O to make a solution that is 8.44 m ethanol.
molality = moles/kg solvent.
moles = g/molar mass.
You will need the density to convert g ethanol to volume.
Post you work if you run into trouble.
To find the volume of the solute ethanol needed, we can use the formula for molarity:
Molarity (M) = moles of solute / volume of solvent
In this case, we're given the molarity (8.44 m), the volume of solvent (0.546 L), and we need to find the volume of solute ethanol.
First, let's rearrange the formula to solve for moles of solute:
Moles of solute = Molarity x volume of solvent
Now, let's calculate the moles of solute ethanol:
Moles of solute ethanol = (8.44 m) x (0.546 L)
Next, we need to convert moles of solute ethanol to volume using the formula:
Volume = moles of solute / molar mass
The molar mass of ethanol (C₂H₆O) is 46.07 g/mol.
Moles of solute ethanol = (8.44 m) x (0.546 L) = 4.61 mol
Volume of solute ethanol = 4.61 mol / 46.07 g/mol
Finally, let's convert the mass of solute ethanol to volume using the density of ethanol:
Density of ethanol = 0.789 g/mL
Mass of solute ethanol = 4.61 mol x 46.07 g/mol = 212.32 g
Volume of solute ethanol = 212.32 g / 0.789 g/mL
To end up with the answer in liters, we divide by 1000:
Volume of solute ethanol = (212.32 g / 0.789 g/mL) / 1000
Therefore, the volume of the solute ethanol needed to make the solution is approximately 0.269 L.