How much work (in joules) is done in moving a charge of 2.5μC a distance of 35 cm along an equipotential at 12~V?
Zero. No force is required to move a charge along an equipotential surface.
Well, let's calculate it in a slightly unconventional way, shall we? Instead of using all those fancy equations, let's picture the scenario.
Imagine a little charge, let's call it "Mr. Zappy", has to move along an equipotential with a potential difference of 12 volts. Mr. Zappy is carrying a sign that says "2.5 μC Charge". Now, 35 cm might not seem like a lot to you and me, but for Mr. Zappy, it's a daunting journey.
As Mr. Zappy starts moving, imagine him sweating, panting, and muttering, "Why me? Why can't I just stay put like all the other charges?" Funny enough, moving charges is hard work for them.
Now, let's crunch some numbers. The potential difference (V) between two points is given as 12 volts. And the charge (Q) is 2.5 μC.
So, the work (W) done in moving Mr. Zappy can be calculated using the equation: W = Q * V.
Plugging in the numbers, we get:
W = 2.5 μC * 12 volts.
Now, to make the units more friendly, let's convert that to joules. We know that 1 μC (microcoulomb) is equal to 1e-6 Coulombs. And 1 volt is equal to 1 joule per coulomb.
So, W = (2.5 * 1e-6 C) * (12 J/C).
Multiplying it out, we get:
W = 3e-5 J * 12 J/C.
And the final answer is:
W = 0.00036 J.
So, Mr. Zappy had to do approximately 0.00036 Joules of work, which might not seem like a lot to us, but it's a marathon for charges like him!
To calculate the work done in moving a charge along an equipotential, we can use the formula:
Work = Electric charge * Voltage difference
Given:
- Charge, q = 2.5 μC = 2.5 x 10^-6 C
- Distance, d = 35 cm = 0.35 m
- Voltage, V = 12 V
Step 1: Convert charge to coulombs
2.5 μC = 2.5 x 10^-6 C
Step 2: Calculate the work done
Work = (2.5 x 10^-6 C) * (12 V)
Work = 3 x 10^-5 C * V
Step 3: Convert work to joules
We know that 1 C * V = 1 J
Therefore,
Work = 3 x 10^-5 J
The work done in moving a charge of 2.5μC a distance of 35 cm along an equipotential at 12 V is 3 x 10^-5 joules.
To calculate the work done in moving a charge along an equipotential, we use the formula:
Work = Charge * Voltage
In this case, the charge is 2.5μC (microCoulombs) and the voltage is 12~V.
Before we calculate the work, we need to convert the charge from microCoulombs (μC) to Coulombs (C). Remember that 1μC is equal to 10^-6C. So, 2.5μC is equal to 2.5 * 10^-6C.
Now we can calculate the work:
Work = (2.5 * 10^-6C) * (12~V)
Multiplying the charge by the voltage, we get:
Work = 3 * 10^-5 C * V
The unit for work is Joules (J). So the final answer is:
Work = 3 * 10^-5 J
Therefore, the work done in moving a charge of 2.5μC a distance of 35 cm along an equipotential at 12~V is 3 * 10^-5 Joules.