Please help me? Chicken Dinners. High Flyin' Wings charges $12 for a bucket of chicken wings and $7 for a chicken dinner. After filling 28 orders for buckets and dinners during a football game, the waiters have collected $281. How many buckets and dinners did they sell?
W = # of wings buckets sold
D = # of dinners sold
W + D = 28
12 W + 7 D = 281
Solve
i think the answer is 63 im not really sure i need help solving this.
Let's assume the number of buckets of chicken wings sold is represented by 'x', and the number of chicken dinners sold is represented by 'y'.
According to the given information, the cost of each bucket of chicken wings is $12, so the total cost of buckets can be calculated as 12 * x.
Similarly, the cost of each chicken dinner is $7, so the total cost of dinners can be calculated as 7 * y.
The total collected amount from selling buckets and dinners is $281, so we can write the equation: 12x + 7y = 281.
We also know that a total of 28 orders were made, so we can write another equation: x + y = 28.
Now we can solve these two equations using substitution or elimination to find the values of 'x' and 'y', representing the number of buckets and dinners sold.
To find out how many buckets and dinners High Flyin' Wings sold, we can set up a system of equations based on the given information.
Let's say the number of buckets sold is "b" and the number of dinners sold is "d".
According to the given information, the cost of each bucket of chicken wings is $12 and the cost of each chicken dinner is $7. The total revenue from the sale of buckets can be calculated by multiplying the cost of each bucket by the number of buckets sold, which gives us 12b. Similarly, the revenue from the sale of dinners can be calculated by multiplying the cost of each dinner by the number of dinners sold, which gives us 7d.
We also know that there were a total of 28 orders. So, the sum of the number of buckets and the number of dinners is 28, which can be expressed as: b + d = 28.
Additionally, the total revenue collected from the sale of buckets and dinners is $281. Therefore, the sum of the revenue from the buckets and the revenue from the dinners is $281, which can be expressed as: 12b + 7d = 281.
Now, we have a system of equations:
Equation 1: b + d = 28
Equation 2: 12b + 7d = 281
To solve this system, we can use substitution, elimination, or any other suitable method. Let's use substitution.
First, we can rearrange Equation 1 to express b in terms of d: b = 28 - d.
Substituting this expression for b in Equation 2, we get:
12(28 - d) + 7d = 281.
Now, we can simplify and solve for d:
336 - 12d + 7d = 281.
-5d = 281 - 336.
-5d = -55.
d = -55 / -5.
d = 11.
Now that we have the value of d, we can substitute it back into Equation 1 to find the value of b:
b + 11 = 28.
b = 28 - 11.
b = 17.
Therefore, High Flyin' Wings sold 17 buckets of chicken wings and 11 chicken dinners during the football game.