Q1

In order to determine the concentration of acetic acid in a sample of vinegar, a student titrated a sample of vinegar with potassium hydroxide solution. Dada from four trials was collected and recorded in a data table.

Titiration of 10.0 mL of CH3COOH(aq) with 0.250 mol/L KOH (aq)
trial 1, 2 3 4
Fianl Reading(ml) 14.5 24.0 39.4 40.1
Intial Reading (mL) 0.5 11.5 27.0 27.8
Volume of KOH (mL) 14.0 12.5 12.4 12.3

Based on the data, it can be concluded that the concentration of vinegar is
A. 0.250 mol/L
B. 0.310 mol/L
C. 0.320 mol/L
D. 0.620 mol/L

Q2.
Use the following information to asnwer the question

Four flasks Containing 100 mL of HCL(aq)

Flask 1 = 2.5 mol/L
Flask 2= 0.20 mol
Flask 3= 200 ppm
Flask 4= 2.0g

What is the order of the flasks containg the highest to the lowest concentration of acid? Enter your answer as four digits.

_ _ _ _

Acetic acid is CH3COOH and it is the right end H that is the acidic one. I will call that H and let Ac stand for the remainder of the molecule.
HAc + KOH ==> H2O + KAc

mols KOH = L x M.
You have L and you have molarity.

Since the ratio of HAc to KOH is 1:1, then mols KOH also equals mols HAc.

Then, remembering the definition of molarity = M = mols/L, simply substitute mols and L is 10.0 mL (convert to L). You will need to calculate each of the four titrations and you will obtain four values. One of the values is not very close to the others; I don't know if you are to use statistics to see if that one is an outlier or not. I assume you will know what to do with the numbers.

Q2. You must convert each of the quantities to mols/L. The first one is done. The second one is 0.20 mol/100 mL = 0.20 mol/0.1 L = 2.0 M
The third one is 200 ppm. Convert to M.
The last one is 2.0 g. Convert to mols and divide by 0.1 L.
Post your work if you get stuck.

KOH + CH3COOH à KCOCH3 +H2O

Q1

To determine the concentration of acetic acid in the vinegar, the student performed a titration using potassium hydroxide solution. By analyzing the data from the titration, we can calculate the concentration of the vinegar.

First, we need to calculate the number of moles of potassium hydroxide used in each trial. This can be done using the formula:

Moles = Volume (L) x Concentration (mol/L)

For trial 1:
Moles KOH = 14.0 mL x 0.250 mol/L = 3.5 mmol

For trial 2:
Moles KOH = 12.5 mL x 0.250 mol/L = 3.125 mmol

For trial 3:
Moles KOH = 12.4 mL x 0.250 mol/L = 3.1 mmol

For trial 4:
Moles KOH = 12.3 mL x 0.250 mol/L = 3.075 mmol

Since the reaction between acetic acid and potassium hydroxide is 1:1, the number of moles of acetic acid is equal to the number of moles of potassium hydroxide.

Next, we need to determine the volume of acetic acid used in each trial. This can be calculated by subtracting the initial reading from the final reading.

For trial 1:
Volume acetic acid = 14.5 mL - 0.5 mL = 14.0 mL

For trial 2:
Volume acetic acid = 24.0 mL - 11.5 mL = 12.5 mL

For trial 3:
Volume acetic acid = 39.4 mL - 27.0 mL = 12.4 mL

For trial 4:
Volume acetic acid = 40.1 mL - 27.8 mL = 12.3 mL

Now, we can calculate the concentration of acetic acid using the formula:

Concentration (mol/L) = Moles / Volume (L)

For trial 1:
Concentration = 3.5 mmol / 14.0 mL = 0.25 mol/L

For trial 2:
Concentration = 3.125 mmol / 12.5 mL = 0.25 mol/L

For trial 3:
Concentration = 3.1 mmol / 12.4 mL = 0.25 mol/L

For trial 4:
Concentration = 3.075 mmol / 12.3 mL = 0.25 mol/L

Since all the trials give the same concentration of 0.25 mol/L, we can conclude that the concentration of acetic acid in the vinegar is A. 0.250 mol/L.

Q2

To determine the order of flasks from highest to lowest concentration of acid, we need to convert all the quantities to moles per liter (mol/L).

Flask 1: 2.5 mol/L (already in mol/L)
Flask 2: 0.20 mol divided by 0.1 L = 2.0 mol/L
Flask 3: 200 ppm = 200 mg/L = 0.2 g/L. Convert grams to moles: 0.2 g / molar mass (HCl) = 0.2 g / 36.46 g/mol ≈ 0.0055 mol/L
Flask 4: 2.0 g / molar mass (HCl) = 2.0 g / 36.46 g/mol ≈ 0.055 mol/L

Now, we have the following concentrations:
Flask 1: 2.5 mol/L
Flask 2: 2.0 mol/L
Flask 3: 0.0055 mol/L
Flask 4: 0.055 mol/L

From highest to lowest, the order of the flasks containing the highest concentration of acid is:
Flask 1, Flask 2, Flask 4, Flask 3.

Therefore, the order is 1243.