Evaluate the definite integral.
xe^(–x^2)dx from 0 to 6
dx x e^-x^2
well d/dx (e^-x^2) = -2 x e^-x^2
so I will guess
(-1/2) e^-x^2 from 0 to 6
(-1/2) e^-36 - (-1/2)e^0
looks like about 1/2
xe^(–x^2)dx from 0 to 6
well d/dx (e^-x^2) = -2 x e^-x^2
so I will guess
(-1/2) e^-x^2 from 0 to 6
(-1/2) e^-36 - (-1/2)e^0
looks like about 1/2