A standard deck of playing cards contains 52 cards in four suits of 13 cards each. Two suits are red and two suits are black. Find each probability.Assume the first card is replaced before the second card is drawn.
1.P(black,queen)
2.P(jack,queen)
How would I solve these type of problems?
this is weird
If you replace the first card and shuffle before drawing the second the two drawings are independent and the chance of black, queen is the product of the queen probability and the black probability.
(4/52)(1/2) which is 2/52
which you could have said immediately because there are 2 black queens in a deck of 52 cards.
May I ask where did you get 4/52 and 1/2?
Four out of 52 cards are queens.
1/2 of all the cards are black.
The two-way table shows the preferred vacation destination for people in different age groups.
Which statement is true?
The probability that a randomly selected adult chose Hawaii as the preferred destination is .
The probability that a randomly selected person who chose Hawaii as the preferred destination is a teenager is .
The probability that a randomly selected child chose Florida as the preferred destination is .
The probability that a randomly selected person who chose Mexico as the preferred destination is a child is .
Mark this and return
The two-way table shows the preferred vacation destination for people in different age groups.
Which statement is true?
The probability that a randomly selected adult chose Hawaii as the preferred destination is .
The probability that a randomly selected person who chose Hawaii as the preferred destination is a teenager is .
The probability that a randomly selected child chose Florida as the preferred destination is .
The probability that a randomly selected person who chose Mexico as the preferred destination is a child is
To solve probability problems like these, you need to determine the total number of possible outcomes and the number of favorable outcomes. Then, you can calculate the probability by dividing the number of favorable outcomes by the total number of outcomes.
Let's solve each problem step by step:
1. P(black, queen)
To calculate the probability of drawing a black queen, we need to find the number of black queens in a standard deck of playing cards.
There are two black queens in a deck, the Queen of Spades and the Queen of Clubs. And since the first card is replaced before the second card is drawn, the probability of drawing a black queen on the first draw is 2/52.
However, we need to find the probability of drawing a black queen on the second draw. Since we are replacing the first card, the number of black queens and total cards will remain the same, so the probability will again be 2/52.
To find the probability of drawing a black queen on both draws, we multiply the probabilities:
P(black, queen) = P(black queen on the first draw) * P(black queen on the second draw)
= (2/52) * (2/52)
= 4/2704
= 1/676
Therefore, the probability of drawing a black queen is 1/676.
2. P(jack, queen)
To calculate the probability of drawing a jack and then a queen, we need to find the number of jacks and queens in a standard deck of playing cards.
There are four jacks (Jack of Hearts, Jack of Diamonds, Jack of Spades, and Jack of Clubs) and four queens (Queen of Hearts, Queen of Diamonds, Queen of Spades, and Queen of Clubs) in a deck. Since the first card is replaced before the second card is drawn, the probability of drawing a jack on the first draw is 4/52, and the probability of drawing a queen on the second draw is also 4/52.
To find the probability of drawing a jack and then a queen, we multiply the probabilities:
P(jack, queen) = P(jack on the first draw) * P(queen on the second draw)
= (4/52) * (4/52)
= 16/2704
= 1/169
Therefore, the probability of drawing a jack and then a queen is 1/169.
That's how you can solve these types of probability problems. Remember to count the possible outcomes and favorable outcomes, and then divide the favorable outcomes by the total outcomes to find the probability.