how many mL of a .25 M HCL would be required to neutralize completely 30mL of a .2 M Ca(OH)2

1 answer

NormalityAcidvolumeacid=NormalitybaseVb

The normalality of the acid here is .25N
the normality of the base here is .40N
solve for volume acid.

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how many mL of a .25 M HCL would be required to neutralize completely 30mL of a .2 M Ca(OH)2

NormalityAcid*volumeacid=Normalitybase*Vb

NormalityAcidvolumeacid=NormalitybaseVb