A solid metal sphere with radius 0.410 carries a net charge of 0.290 Find the magnitude of the electric field at a point 0.116 outside the surface of the sphere.
To find the magnitude of the electric field at a point outside the surface of a charged sphere, we can use the equation for the electric field due to a point charge:
E = k (Q / r^2)
Where:
- E is the magnitude of the electric field
- k is Coulomb's constant, approximately equal to 8.99 x 10^9 Nm^2/C^2
- Q is the net charge of the sphere
- r is the distance from the center of the sphere to the point where we want to calculate the electric field
In this case, the sphere has a net charge of Q = 0.290 C and we want to find the electric field at a point located 0.116 m outside the surface of the sphere (r = 0.410 m + 0.116 m = 0.526 m).
Plugging these values into the equation, we get:
E = (8.99 x 10^9 Nm^2/C^2) * (0.290 C) / (0.526 m^2)
Calculating this expression will give us the magnitude of the electric field at the desired point.
Apply Gauss' law at a distance r = 0.526 m from the center of the sphere.
You should have provided units for the charge. Are they Coulombs or microcoulombs? You also did not provide units for the distances.
Unless you understand the importance of units in physics and enginering you should not be taking these courses. Find a different career.