Some properties of the two compounds are listed below:

Melting point- Compound X= -114*C Compound Y= -138*C
Boiling Point- Compound X= 78*C
Compound Y= -22*C
Net Dipole?- Compound X= Yes
Compound Y= Yes
Functional group: Compound X Alcohol
Compound Y= Ether

i.) Draw plausible Lewis Structure of Compounds X and Y

See comment above.

To draw the plausible Lewis structures of compounds X and Y, you will need to know the molecular formula of each compound. The given information states that Compound X is an alcohol and Compound Y is an ether. Alcohol molecules contain the functional group -OH, while ethers consist of the functional group -O-.

Let's start with Compound X, an alcohol. The general molecular formula of an alcohol is R-OH, where R represents a carbon chain or a substituent. Since the molecular formula for Compound X is not mentioned, I will assume it as CH3OH for simplicity.

To draw the Lewis structure of Compound X:
1. Identify the atoms and arrange them in the correct order.
In this case, we have one carbon (C) atom bonded to one oxygen (O) atom, with three hydrogen (H) atoms bonded to carbon.
CH3OH

2. Determine the total number of valence electrons.
Carbon has 4 valence electrons, Oxygen has 6, and Hydrogen has 1 electron each. So, we have:
(1 carbon atom × 4 electrons) + (1 oxygen atom × 6 electrons) + (3 hydrogen atoms × 1 electron) = 4 + 6 + 3 = 13 valence electrons.

3. Connect the atoms using single bonds.
Carbon is the central atom, so it will be bonded to oxygen by a single bond, and all hydrogen atoms will be bonded to carbon by single bonds.
H - C - O - H

4. Distribute the remaining valence electrons around the atoms to satisfy the octet rule.
Place the remaining 2 electrons on the oxygen atom as a lone pair.
H - C - O
|
H

This is the plausible Lewis structure of Compound X.

Now let's move on to Compound Y, an ether. The general molecular formula of an ether is R-O-R', where R and R' represent carbon chains or substituents. Since the molecular formula for Compound Y is not provided, I will assume it as CH3OCH3.

To draw the Lewis structure of Compound Y:
1. Identify the atoms and arrange them in the correct order.
In this case, we have two carbon (C) atoms bonded to one oxygen (O) atom, with three hydrogen (H) atoms bonded to each carbon.
CH3OCH3

2. Determine the total number of valence electrons.
Carbon has 4 valence electrons, Oxygen has 6, and Hydrogen has 1 electron each. So, we have:
(2 carbon atoms × 4 electrons) + (1 oxygen atom × 6 electrons) + (6 hydrogen atoms × 1 electron) = 8 + 6 + 6 = 20 valence electrons.

3. Connect the atoms using single bonds.
Carbon atoms are the central atoms, so they will be bonded to oxygen by single bonds, and all hydrogen atoms will be bonded to each carbon by single bonds.
H - C - O - C - H
|
H

4. Distribute the remaining valence electrons around the atoms to satisfy the octet rule.
Place the remaining 10 electrons as lone pairs on the oxygen and carbon atoms.
H - C - O - C - H
|
H

This is the plausible Lewis structure of Compound Y.

Note: The actual Lewis structure of the compounds may vary depending on the molecular formula and arrangement of atoms.