A 6.00 M H2SO4 solution has d = 1.34 g/mL. What is the mass percent of H2SO4 in this solution?
density = 1.34 g/mL so 1 L has a mass of what?
1.34 g/mL x 1000 mL = 1340 grams.
How much of that is H2SO4? You had 6.00 moles in that L of solution so 6.00 moles x (98 g/mole) = 588 grams.
So you have 588 g H2SO4 in 1340 g; the percent must be (588/1340)*100 = ??
You need to redo this since I estimated the molar mass of H2SO4 as 98.0 and that isn't exactly right. Check my thinking. Check my work.
thanks it was correct!
Well, let's put our nerdy lab coats on and figure this out together!
To find the mass percent of H2SO4 in a solution, we need to compare the mass of H2SO4 to the total mass of the solution. So, let's start by calculating the mass of H2SO4.
Given that the density (d) of the solution is 1.34 g/mL, we can say that 1 mL of the solution weighs 1.34 grams.
Now, the molarity (M) of H2SO4 is given as 6.00 M, which means it contains 6.00 moles of H2SO4 in 1 liter of solution.
The molar mass of H2SO4 is approximately 98.09 g/mol. So, for every mole of H2SO4, there is a mass of 98.09 grams.
Now, we need to find the mass of H2SO4 in the 1 mL of the solution.
Since the molarity is 6.00 M, there are 6.00 moles of H2SO4 in 1 liter of solution. And since we are only considering 1 mL of the solution, we'll divide the molarity by 1000 to get moles per milliliter.
6.00 moles/L ÷ 1000 mL/L = 0.006 moles/mL
Now we can multiply this with the molar mass to find the mass of H2SO4 in 1 mL of the solution.
0.006 moles/mL × 98.09 g/mol = 0.58854 g/mL
Finally, we divide this mass by the total mass of the solution to get the mass percent.
0.58854 g/mL ÷ 1.34 g/mL × 100% ≈ 43.90%
So, the mass percent of H2SO4 in this solution is approximately 43.90%.
To find the mass percent of H2SO4 in the solution, we need to first calculate the mass of the H2SO4 in a given volume of the solution.
Step 1: Calculate the volume of the solution.
Given that the density (d) of the solution is 1.34 g/mL, we can use the formula:
Volume = Mass / Density
Let's assume we have 1 gram of the solution, then using the given density, the volume of the solution can be calculated as follows:
Volume = 1 g / 1.34 g/mL
Volume ≈ 0.746 mL
Step 2: Calculate the mass of H2SO4 in the solution.
To find the mass of H2SO4 in the solution, we can use the equation:
Mass = Volume × Concentration
Given that the concentration of the solution is 6.00 M, the mass of H2SO4 can be calculated as follows:
Mass = 0.746 mL × 6.00 M
Mass ≈ 4.476 g
Step 3: Calculate the mass percent of H2SO4 in the solution.
The mass percent of H2SO4 in the solution is given by the formula:
Mass Percent = (Mass of H2SO4 / Mass of Solution) × 100
Mass of Solution = Mass of Solution - Mass of H2SO4 (since mass percent is based on total mass)
Mass Percent = (4.476 g / 5.00 g) × 100
Mass Percent ≈ 89.52%
So, the mass percent of H2SO4 in the 6.00 M H2SO4 solution is approximately 89.52%.
To find the mass percent of H2SO4 in the solution, you need to calculate the mass of H2SO4 and the total mass of the solution, and then divide the mass of H2SO4 by the total mass and multiply by 100%.
First, let's calculate the mass of H2SO4 in the solution. Since we know the density of the solution, we can assume that 1 mL of the solution weighs 1.34 g. Therefore, in 1 L (1000 mL) of the solution, there would be 1000 * 1.34 = 1340 g of the solution.
Now, we need to determine the mass of H2SO4 in the solution. The concentration of the H2SO4 is given as 6.00 M, which means that there are 6.00 moles of H2SO4 present in 1 liter of the solution. To convert moles to grams, we need to know the molar mass of H2SO4.
The molar mass of H2SO4 can be calculated by adding up the atomic masses of each element: H (1.01 g/mol) * 2 + S (32.07 g/mol) + O (16.00 g/mol) * 4 = 98.09 g/mol.
Now, we can calculate the mass of H2SO4 in the solution:
Mass of H2SO4 = moles of H2SO4 * molar mass of H2SO4
Since we have 6.00 moles of H2SO4 (given concentration 6.00 M) and the molar mass of H2SO4 is 98.09 g/mol, the mass of H2SO4 would be:
Mass of H2SO4 = 6.00 moles * 98.09 g/mol = 588.54 g
Finally, we can calculate the mass percent of H2SO4 in the solution:
Mass percent of H2SO4 = (Mass of H2SO4 / Total mass of solution) * 100%
The total mass of the solution was previously calculated as 1340 g. Substituting the values:
Mass percent of H2SO4 = (588.54 g / 1340 g) * 100% = 43.93%
Therefore, the mass percent of H2SO4 in the 6.00 M H2SO4 solution is approximately 43.93%.