When copper wire is placed into a silver nitrate solution, silver crystals and copper(II) nitrate solution form. Write the balanced chemical equation for the reaction. (Type your answer using the format CH4 for CH4.)
1 Cu(s) + 2AgNO3(aq = 2Ag(s) + 1Cu(NO3)2(aq)
If a 23.5 g sample of copper is used, determine the theoretical yield of silver.
9 g
The equation you have written for the reaction between Cu and Ag^+ is correct; however, you don't need the coefficient of 1 for Cu and Cu(NO3)2.
For the theoretical yield part, I don't get 9 g; I am unable to determine if that is a typo or not.
1. Convert 23.5 g Cu to moles. moles = grams/molar mass.
2. Using the coefficients in the balanced equation, convert moles Cu to moles Ag.
3. Now convert moles Ag to grams. grams = moles x molar mass.
To determine the theoretical yield of silver, we first need to calculate the molar mass of copper (Cu) and silver (Ag).
The molar mass of copper (Cu) is 63.55 g/mol.
The molar mass of silver (Ag) is 107.87 g/mol.
Next, we need to determine the stoichiometry of the balanced equation. From the equation:
1 mole of copper (Cu) reacts with 2 moles of silver nitrate (AgNO3) to produce 2 moles of silver (Ag).
Now we can calculate the moles of copper (Cu) in the given sample using the molar mass:
moles of copper (Cu) = mass of copper (g) / molar mass of copper (Cu)
moles of copper (Cu) = 23.5 g / 63.55 g/mol = 0.369 moles
Using the stoichiometry of the balanced equation, we can determine the moles of silver (Ag) that can be produced:
moles of silver (Ag) = moles of copper (Cu) x (2 moles of Ag / 1 mole of Cu)
moles of silver (Ag) = 0.369 moles x (2 moles of Ag / 1 mole of Cu) = 0.738 moles
Finally, we can calculate the theoretical yield of silver (Ag) using the molar mass:
theoretical yield of silver (Ag) = moles of silver (Ag) x molar mass of silver (Ag)
theoretical yield of silver (Ag) = 0.738 moles x 107.87 g/mol = 79.57 g
Therefore, the theoretical yield of silver (Ag) is 79.57 g.
To determine the theoretical yield of silver, we need to use the balanced chemical equation and the concept of stoichiometry.
First, let's calculate the molar mass of copper (Cu) and silver (Ag):
- Molar mass of Cu: 63.55 g/mol
- Molar mass of Ag: 107.87 g/mol
Next, we need to convert the given mass of copper (23.5 g) into moles:
- Moles of Cu = Mass of Cu / Molar mass of Cu
= 23.5 g / 63.55 g/mol
= 0.369 mol
Using the coefficients in the balanced chemical equation, we can determine the molar ratio between Cu and Ag:
- From the balanced equation: 1 mol Cu produces 2 mol Ag
Now, we can set up a proportion to determine the theoretical yield of Ag:
- (0.369 mol Cu) / (1 mol Cu) = (x mol Ag) / (2 mol Ag)
Solving for x:
- (0.369 mol Cu) / (1 mol Cu) = (x mol Ag) / (2 mol Ag)
- x = (0.369 mol Cu) * (2 mol Ag) / (1 mol Cu)
- x = 0.738 mol Ag
Finally, we can convert the moles of Ag to grams:
- Theoretical yield of Ag = Moles of Ag * Molar mass of Ag
= 0.738 mol * 107.87 g/mol
≈ 79.60 g
Therefore, the theoretical yield of silver is approximately 79.60 grams.