name and give the molecular formula for the alkane with a molar mass of 44 g/mol?
Is that C3H8? I call that n-propane but you realize there are isomers of propane.
To determine the name and molecular formula of an alkane with a molar mass of 44 g/mol, we need to follow a few steps.
Step 1: Determine the number of carbon atoms.
- Alkanes have the general formula CnH2n+2, where "n" represents the number of carbon atoms.
- Since the molar mass is 44 g/mol, this means the molecular formula will have a C:H ratio of 1:2.
- The atomic mass of carbon (C) is approximately 12 g/mol, and the atomic mass of hydrogen (H) is approximately 1 g/mol.
- Therefore, the molar mass of the carbon atoms in the alkane will be 12n g/mol, and the molar mass of the hydrogen atoms will be (1 * 2n) g/mol.
- We need to find the value of "n" that satisfies the equation: 12n + (1 * 2n) = 44 g/mol.
Step 2: Solve the equation.
- Simplifying the equation, we have 14n = 44.
- Dividing both sides of the equation by 14, we get: n = 44 / 14 = 3.14.
- Since we cannot have a fraction of a carbon atom, we need to round down to the nearest whole number. So, n = 3.
Step 3: Determine the molecular formula and name.
- Now that we have the number of carbon atoms (n = 3), let's calculate the number of hydrogen atoms.
- Using the formula CnH2n+2, we find that we will have 2 * 3 + 2 = 8 hydrogen atoms.
- Therefore, the molecular formula for the alkane is C3H8.
- Following the naming rules for alkanes, the alkane with three carbon atoms is called propane.
So, the alkane with a molar mass of 44 g/mol is propane, and its molecular formula is C3H8.