A student placed 14.0 of glucose () in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.- mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 55.0- sample of this glucose solution was diluted to 0.500 . How many grams of glucose are in 100. of the final solution?

What are the units for crying out loud?

Are all of them 100 mL. I will assume that is what you meant except for the dilution which I assume is 0.500 L or 500 mL.
14 g/100 = 0.14 g/mL
You took 55 mL of that so you have in the aliquot of 55 mL exactly 0.14 g/mL x 55 mL = 7.70 g. Now you put that 7.70 g into 500 mL so you now have 7.70 g/500 mL = 0.0154 g/mL. If you want the amount in 100 mL it is just 100 x that. Check my thinking.

0.0154

To find the number of grams of glucose in 100. mL of the final solution, we can use the concept of dilution and the given information.

Let's calculate the concentration of the original glucose solution first:

Concentration (C1) = (mass of solute / volume of solution) = (14.0 g / 100. mL)

Now, let's determine the number of moles of glucose in the original 55.0 mL sample:

Number of moles (n1) = concentration (C1) × volume (V1)
= (14.0 g / 100. mL) × 55.0 mL

To dilute the 55.0 mL sample to a total volume of 0.500 L (500 mL) with water, we can use the dilution formula:

C1V1 = C2V2

Now, let's solve for the final concentration (C2):

C2 = (C1V1) / V2
= [(14.0 g / 100. mL) × 55.0 mL] / 500. mL

To find the number of grams of glucose in 100. mL of the final solution, we need to determine the number of moles of glucose in that volume and convert it into grams using the molar mass of glucose:

Number of moles (n2) = final concentration (C2) × volume (V2)
= [(14.0 g / 100. mL) × 55.0 mL] / 500. mL × 100. mL

Finally, we can calculate the mass of glucose in 100. mL of the final solution:

Mass = number of moles (n2) × molar mass of glucose
= ([(14.0 g / 100. mL) × 55.0 mL] / 500. mL × 100. mL) × molar mass of glucose

Note: The molar mass of glucose is 180.16 g/mol.

By substituting the values into the equation, you will get the final answer.

To find out how many grams of glucose are in 100. ml of the final solution, we need to use the given information and apply the concept of dilution.

First, let's determine the concentration of glucose in the 55.0 ml sample that was diluted. We know that the 55.0 ml sample was diluted to 0.500 M, which means the final concentration of glucose is 0.500 moles per liter (M).

To calculate the number of moles of glucose in the 55.0 ml sample, we can use the equation:

moles = concentration x volume (in liters)

Converting the volume of the sample to liters:

55.0 ml = 0.055 liters

Now we can calculate the moles of glucose in the 55.0 ml sample:

moles = 0.500 M x 0.055 L = 0.0275 moles

Next, we can calculate the number of grams of glucose in the 55.0 ml sample using the molar mass of glucose. The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.

grams = moles x molar mass

grams = 0.0275 moles x 180.16 g/mol = 4.95 grams

Now that we know the mass of glucose in the 55.0 ml sample, we can determine the concentration of glucose in the final solution. Since the volume of the final solution is 100.0 ml, the concentration will be:

concentration = mass/volume

concentration = 4.95 g/100.0 ml = 0.0495 g/ml

Therefore, there are 0.0495 grams of glucose in 100.0 ml of the final solution.